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ivolga24 [154]
4 years ago
7

Two Vertical buildings 91 metres apart are136 metres and 192 metres high respectively. Find the angle of elevation form the top

of the shorter building o the top of the taller building to the nearest degree

Mathematics
1 answer:
pickupchik [31]4 years ago
3 0

Answer:

≈ 32°

Step-by-step explanation:

Distance between buildings= 91 m

Elevation difference= 192 m- 136 m= 56 m

Right triangle ΔABC is formed by connecting 3 points, see attached

∠C is one to be calculated

tan C=AB/AC= 56/91

tan C= 0.62

∠C ≈ 32°

-------------------

<em>∠B = (90°-32°)= 58° in case I misread which angle to be found</em>

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Answer:

The correct option is (a).

Step-by-step explanation:

The vertices are equidistant from the circumcenter.

Circumcenter of a triangle is a point where the perpendicular bisectors are intersection each other.

In figure (a) the point P is the intersection point of all perpendicular bisector, therefore point P is the circumcenter of triangle ABC and the point P is equidistant from A,B and C.

Therefore option (a) is correct.

In figure (b) the point P is the intersection point of all perpendicular, therefore point P is not the circumcenter of triangle ABC.

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Therefore option (c) is incorrect.

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