Two Vertical buildings 91 metres apart are136 metres and 192 metres high respectively. Find the angle of elevation form the top
of the shorter building o the top of the taller building to the nearest degree
1 answer:
Answer:
≈ 32°
Step-by-step explanation:
Distance between buildings= 91 m
Elevation difference= 192 m- 136 m= 56 m
Right triangle ΔABC is formed by connecting 3 points, see attached
∠C is one to be calculated
tan C=AB/AC= 56/91
tan C= 0.62
∠C ≈ 32°
-------------------
<em>∠B = (90°-32°)= 58° in case I misread which angle to be found</em>
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