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3 years ago

11

Helpppppppp please i have sot math help :(

1 answer:

kobusy [5.1K]3 years ago

8 0

Answer:

Increase by 33.33,

Decreased by 25%,

Decreased by 10%,

Decreased by 20%,

9,

66dhs,

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Prove. sin³A-cos³A/sinA-cosA = 1+sinAcosA

katovenus [111]

Answer:

$\frac{ \sin {}^{3} A - \cos {}^{3} A }{ \sin A - \cos A} \\ \\ { \sf{ = \frac{ {( \sin A - \cos A)}^{3} + 3 \sin A \cos A( \sin A - \cos A)}{ \sin A - \cos A} }} \\ \\ = { {( \sin A - \cos A)}^{2} + 3 \sin A \cos A} \\ { \sf{ = ( \sin {}^{2} A + \cos {}^{2} A) - 2 \sin A \cos A + 3\sin A \cos A}} \\ = { \sf{1 +\sin A \cos A }}$

#hence proved

7 0

3 years ago

What areC12, C31, and C22 of matrix C?

Liono4ka [1.6K]

Compute the sum to simplify C :

$C = \begin{bmatrix}16-0.5 & 9+0 \\ -3+5 & 0 + 8 \\ 4-3 & -10+14\end{bmatrix} = \begin{bmatrix}15.5 & 9 \\ 2 & 8 \\ 1 & 4\end{bmatrix}$

Now, $c_{ij}$ is the entry of the matrix in row i and column j, so

$C = \begin{bmatrix}15.5 & \boxed{9} \\ 2 & 8 \\ 1 & 4\end{bmatrix} \implies c_{12} = 9$

$C = \begin{bmatrix}15.5 & 9 \\ 2 & 8 \\ \boxed{1} & 4\end{bmatrix} \implies c_{31} = 1$

$C = \begin{bmatrix}15.5 & 9 \\ 2 & \boxed{8} \\ 1 & 4\end{bmatrix} \implies c_{22} = 8$

5 0

1 year ago

What is 67 x 578 divide by 5?

MA_775_DIABLO [31]

Answer:

7745.2

Step-by-step explanation:

you need to multiply 67 by 578 which is 38726. then you divide it by 5. In short, you can just use calculator or you can use scratch paper.\

3 0

3 years ago

Read 2 more answers

Help help please will give brainliest PLEASE DON'T ANSWER IF YOU DON'T KNOW THE ANSWER

sergey [27]

Answer:

0 is the answer. I think.

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3 years ago

What temperature is 15 degrees lower than 7 degrees Celsius?

natali 33 [55]

Subtract 15 from 7 and you get -8 So the answer is -8 degre C

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3 years ago