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2 years ago

2⁄3 + 1⁄6 + 2⁄8 = ??

Mathematics

2 answers:

lubasha [3.4K]2 years ago

4 0

Answer:

Step-by-step explanation:

use ur brain

Over [174]2 years ago

3 0

Answer:

I whole 1/12

Step-by-step explanation:

2/3+1/6+2/8

= 16/24+4/24+6/24 = 26/24 = 1 whole 2/24

= I whole 1/12

( I hope this was helpful) >;D

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A rectangular soccer field is 120 ft long by 64 ft wide. What dimensions would a scale drawing of the soccer field be if the fie

timofeeve [1]

Answer:

Hence dimension on drawing= 12 in by 6.4 in

Step-by-step explanation:

Actual dimension of the soccer field is 120 ft by 64 ft

Scale during drawing = 1in to 10 ft

Hence dimension on drawing = 120/10 by 64/10 = 12 in by 6.4 in

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3 years ago

47/8 as a mixed number

tresset_1 [31]

47/8 is an improper fraction so we need to divide 47 by 8 to get an mixed number.
8 go into 47, 5 times because 5*8 equals 40.
47-40 is 7 that is the left over.
5 7/8 is your mixed number.

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3 years ago

-3(-2x-8)-(-5x+6) what are the steps to solve this

Eddi Din [679]

First distribute the -3 and the - sign

6x + 24 + 5x - 6

Combine like terms

11x + 18

8 0

2 years ago

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Problem 5. A skating rink in the shape shown has an area of

nexus9112 [7]

Answer:

$P=\dfrac{\pi r^2+2800}{r} $ ft$

Step-by-step explanation:

Let the length of the rectangular part =l

The width will be equal to the diameter of the semicircles.

Area of the Skating Rink= $2(\frac{\pi r^2}{2})+(lX2r)$

Therefore:

$\pi r^2+2lr=2800\\2lr=2800-\pi r^2\\$Divide both sides by 2r\\l=\dfrac{2800-\pi r^2}{2r}$

Perimeter of the Shape =Perimeter of two Semicircles + 2l

$=2\pi r+2\left(\dfrac{2800-\pi r^2}{2r}\right)\\=2\pi r+\dfrac{2800-\pi r^2}{r}\\=\dfrac{2\pi r^2+2800-\pi r^2}{r}\\=\dfrac{\pi r^2+2800}{r}$

The perimeter of the rink is given as:

$P=\dfrac{\pi r^2+2800}{r} $ ft$

4 0

2 years ago

The shaded area of the shape below rounded to the nearest whole number is:<br>8 cm<br>8 cm

maks197457 [2]

Answer:

Step-by-step explanation:

8x8=64

3 0

2 years ago

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