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azamat
3 years ago
9

2⁄3 + 1⁄6 + 2⁄8 = ??

Mathematics
2 answers:
lubasha [3.4K]3 years ago
4 0

Answer:

a

Step-by-step explanation:

use ur brain

Over [174]3 years ago
3 0

Answer:

I whole 1/12

Step-by-step explanation:

2/3+1/6+2/8

= 16/24+4/24+6/24 = 26/24 = 1 whole 2/24

= I whole 1/12

( I hope this was helpful) >;D

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Ohn has taken out a loan for college. He started paying off the loan with a first payment of $100. Each month he pays, he wants
Gwar [14]

Answer:

Ohn has paid $5730 in first 20 installments

Step-by-step explanation:

As per the question Ohn payed the first installment =$100

Next month Ohn payed the installment = 1.1×$100

Similarly subsequent installment =1.1×1.1×$100

So we can write first 20 installments as

⇒100+100×1.1+100×1.1²+100×1.1³.........+100×1.1^{20}

And we know in geometric series

1+x²+x³+...........x^{20} = (1-x^{n-1})÷(1-x)

Therefore sum of first 20 installments will be

⇒100(1+1.1²+1.1³............1.1^{20} =(1- 1.1^{20})÷(1-1.1)

= 100(1-6.73)÷(-.1)

=100×5.73÷.1

= $5730

So Ohn has paid $5730


7 0
3 years ago
Can you help me? I will give brainliest!
zzz [600]

Answer:

√1

Step-by-step explanation:

If you do the fractions by squaring them then you get fractions that equal 1:

5/13^2 = 25/169

12/13^2 = 144/169

144/169 + 25/169 = 169/169 = 1

√1

6 0
3 years ago
Px + qx = r<br> solve for q
borishaifa [10]

Answer:

q = (r - px) / x

or you could write it as q =  (r/x) - p

Step-by-step explanation:

px + qx = r

qx = r - px

q = (r - px) / x

7 0
3 years ago
Read 2 more answers
Solve for x. enter your answer in interval notation using grouping symbols. x^2+15x&lt;-36
Oliga [24]
X²+15x+36<0

at first solve quadratic equation

D=b²-4ac= 225-4*1*36= 81

x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3

we can write x²+15x+36<0 as (x+12)(x+3)<0

(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
 1 case)      x+12<0, and x+3>0,                                            
                       x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set

or second case)  x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3)  they are crossing , so (-12, -3)  is a solution of this inequality


3 0
4 years ago
Heeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeelp 1
BARSIC [14]

Answer:

the third one

Step-by-step explanation:

y represents the number plus 5 and the x represents the other number

4 0
2 years ago
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