What is the volume of the following triangular prism?

Mathematics

1 answer:

Firdavs [7]3 years ago

7 0

Answer:

Step-by-step explanation:

In order to calculate the volume of a triangular prism you need 2 things:

The triangles area and the prism's height.

Any prism's volume can be calculated by multiplying its base area with its height.

The Area of a triangle can be calculated in different ways.

The most used and "normal" way is:

(width * height) / 2

Another way is by using herons formula, which looks like this:

a, b, c = different sides of the triangle (length)

s = (a + b + c) / 2

a = $\sqrt{s (s-a)(s-b)(s-c)}$

When you have the prism's base area ( $b_{a}$ ) you just have to multiply:

$b_{a}*h=V$

(V = volume)

If you have any questions, just ask them in the comments below.

Have a good day! (●'◡'●)

You might be interested in

What is the perimeter of a regular heptagon with a side length of 9 inches?

jok3333 [9.3K]

What kind of Question is that. That is some real math right there.

6 0

3 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$