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Dominik [7]
3 years ago
11

Combine the like terms to create an equivalent expression: -3r- 6+ (-1)

Mathematics
2 answers:
Norma-Jean [14]3 years ago
7 0

Answer:

-3r+5 is that answer hdj

GenaCL600 [577]3 years ago
5 0

Answer:

-3x-7

Step-by-step explanation:

-6 + -1 = -7

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What is -7.08 as a fraction in simplest form
zhenek [66]
-7.08 as a fraction in simplest form would be -177/25
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All repeating decimals are irrational True or false
egoroff_w [7]

Answer:

Step-by-step explanation: true

3 0
3 years ago
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What are the coordinates of the endpoints of the midsegment for △DEF that is parallel to DE¯¯¯¯¯?
Vladimir [108]

Answer:

(-1, 2) and (-1, 3.5)

Step-by-step explanation:

The triangle ΔDEF spans 4 squares horizontally.

So, the midsegment of ΔDEF will coincide with the line 4/2 = 2 squares from the vertex F.

Note that the <em>x </em>coordinate of the vertex F is -3 and 2 units to the right of F is -1.

Therefore, the midsegment of ΔDEF coincides with the line <em>x</em> = -1.

So, the <em>x</em> coordinates of the end points of the midsegment are -1.

Let's find the <em>y</em> coordinates of the end points.

From the given figure, it is clear that the mid point of FD is half way between 3 and 4 and hence it is 3.5.

Mid point of FE is 2.

So, the co-ordinates of the end points of the midsegment are (-1, 2) and (-1, 3.5).



8 0
3 years ago
Read 2 more answers
Question 1 on my integrated geometry test
NemiM [27]

Answer:

B. 15 cm

Step-by-step explanation:

Hypotenuse (h) = 17 cm

perpendicular (p) = 8 cm

base (b) = YZ = ?

We know that by using Pythagoras theorem

b = √ (h² - p²)

= √ ( 17² - 8²)

= √225

= 15 cm

YZ = 15 cm

Hope it will help :)❤

8 0
3 years ago
Read 2 more answers
Suppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.5
pentagon [3]

Given:

\begin{gathered} mean(\mu)=2.57 \\ Standard\text{ }deviation(\sigma)=0.44 \end{gathered}

To Determine: The percentage of the students that have grade point averages that are at least 1.68

Solution

Please note that according to empirical rule,

\begin{gathered} \mu-\sigma=68\% \\ \mu-2\sigma=95\% \\ \mu-3\sigma=99.7\% \end{gathered}

\begin{gathered} 2.57-0.44=2.13 \\ 2.57-2(0.44)=2.57-0.88=1.69 \end{gathered}

For at least 1.69, we can see from the above, calculation that it is the mean subtracted from twice the standard deviation that gives 1.69. Therefore, the percentage for at least 1.69 would be the average of the percentage for twice and thrice of the standard deviation from the mean. This is as calculated below

\begin{gathered} Average=\frac{(99.7+95)\%}{2} \\ Average=\frac{194.7}{2} \\ Average=97.35\% \end{gathered}

5 0
1 year ago
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