Question

Which of the following are solutions to the equation below?

Answer 1

Answer:

B and C

Step-by-step explanation:

First, we need to get the left side equal to zero. Take away 25 from each side to get $4x^2+12x-16 = 0$.

We can use the quadratic equation of $\frac{-b+ -\sqrt{b^2-4ac} }{2a}$ to find the solutions.

Plug them in to get $\frac{-12+-\sqrt{144 -(-256)} }{8}$.

Simplify.

$\frac{-12+-\sqrt{400} }{8}$

$\frac{-12+-20}{8}$

$\frac{8}{8}$ or $\frac{-32}{8}$

1 and -4

x = 1 and -4

Answer 2

That 4x is 25 makes 20