Question

Someone knows this one? help me please help help :(thank you so much​

Answer 1

Answer:  d

Step-by-step explanation:

$KE=\dfrac{1}{2}mv^2\\\\\\\bigg(\dfrac{2}{m}\bigg)KE=\bigg(\dfrac{2}{m}\bigg)\dfrac{1}{2}mv^2\\\\\\\bigg(\dfrac{2}{m}\bigg)KE=v^2\\\\\\\sqrt{\bigg(\dfrac{2}{m}\bigg)KE}=\sqrt{v^2}\\\\\\\sqrt{\bigg(\dfrac{2}{m}\bigg)KE}=v$