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Amiraneli [1.4K]
3 years ago
15

What are the x intercepts if y is 16x takeaway 8x squared?​

Mathematics
1 answer:
Norma-Jean [14]3 years ago
7 0

Answer:

The x-intercepts are (0, 0) and (2, 0)

Step-by-step explanation:

The function is y = 16x - 8x^2.

To find the x-intercepts, we set this function equal to zero (0) and solve the resulting equation for x:

16x - 8x^2 = 8x(2 - x) = 0.

Then 8x = 0 yields x = 0 and 2 - x = 0 yields x = 2

The x-intercepts are (0, 0) and (2, 0)

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What is it called when writing a number by adding the value of each digit
Neko [114]

Answer:

Expanded form

Step-by-step explanation:

Expanded form or expanded notation is a system of writing numbers to see the value of each individual digits. The number are written in the form of tens, hundreds and ones etc. The expanded form of 44 will be 40 +4 where 4 is at ones place and 40 is at tens place.

5 0
3 years ago
8. Here is a graph of the equation 3x - 2y = 12.
Readme [11.4K]

Answer:

A,B,D

Step-by-step explanation:

By replacing the points in the current equation you can get true statements which are correspondent to answer A,B,D

7 0
1 year ago
Any number multiplied by<br> (A) 5<br> (B) 6<br> (C) 7<br> (D) 9<br> has only even products.
yaroslaw [1]

Answer:

c 6

Step-by-step explanation:

6,12,18,24,39,36,42,48

7 0
3 years ago
Read 2 more answers
Can some one help me i need it done by today
lapo4ka [179]

Answer:


Number 9: 1.25 miles

Step-by-step explanation:

In total Brian hiked 16 miles

In total Christine hiked 14.75

So, 16 - 14.75 = 1.25

Overall, Brian hiked 1.25 more miles than Christine.

7 0
3 years ago
Which of the following can be a Pythagorean triplets?:
PolarNik [594]

<h2>Answer :-</h2>

As we know that,

Pythagoras triplet

1) a² + b² = c²

Let

\sf \: {2}^{2} + {2}^{2} = {4}^{2}

\sf \: 4 + 4 = 16

  • 8 ≠ 16
<h3>Hence, A can't be Pythagoras triplet</h3>

2) a² + b² = c²

\sf \:5 {}^{2} + {12}^{2} = {13}^{2}

\sf \: 25 + 144 = 169

  • 169 = 169
<h3>Therefore, B can be Pythagoras triplet</h3>

3)a² + b² = c²

\sf {3}^{2} + {5}^{2} = {6}^{2}

\sf 9 + 25 = 36

  • 34 ≠ 36
<h3>Hence, C can't be Pythagoras triplet</h3>

4) a² + b² = c²

\sf {5}^{2} + {4}^{2} = {7}^{2}

\sf \: 25 + 16 = 49

  • 41 ≠ 49
<h3>Hence, D can't be Pythagoras triplet</h3>

<h2 /><h2>Therefore :-</h2>

Only B can be Pythagoras triplet.

3 0
3 years ago
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