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3 years ago

The dot plot shows the numbers of text message received by students over the weekend .

Mathematics

2 answers:

alexdok [17]3 years ago

8 0

Answer:

basdasidw buga

Step-by-step explanation:

Viktor [21]3 years ago

6 0

Answer:

Part A: The amount of students represented is around 68-69

Part B: You Can collect the data by using the dot plot, the units are text messages

Part C: How many students receive text messages over the weekend? This is a statical question because there’s more than one answer.

I’m not sure by the way, I hope it helps anyway. If this doesn’t work out then sorry :)

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Write a trinomial which is degree 2, where the coefficient of the highest degree term is 7.

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Answer:

7x^2 - 2x - 3.

Step-by-step explanation:

Starts with 7x^2 then a term in x then a constant.

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3 years ago

Find the ratio of x to y is 5y=3x

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Answer:

$\frac{x}{y}$ = $\frac{5}{3}$

Step-by-step explanation:

given 5y = 3x ( divide both sides by 3 )

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Each figure below is made up of congruent trapezoids. Find the area of each figure.

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4 years ago

2x + 2 = -52 whats the value of x

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4 years ago

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

Correct answer:

A. I and II

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

Correct answer:

A. I and II

4 0

3 years ago