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levacccp [35]
3 years ago
10

The width of a triangle of 7 feet longer than its length. Find the dimensions of the rectangle such that the perimeter of the re

ctangle is 162 feet
Mathematics
1 answer:
AveGali [126]3 years ago
4 0

Answer:

Length = 37 feets

Width = 44 feets

Step-by-step explanation:

Given that :

Length = l

Width, w = 7 + l

Perimeter , P of rectangle = 162

Recall:

Perimeter of a rectangle = 2(l + w)

P = 2(l + w)

162 = 2(l + (7 + l))

162 = 2(l + 7 + l)

162 = 2(7 + 2l)

162 = 14 + 4l

162 - 14 = 4l

148 = 4l

l = 148 / 4

l = 37 feets

Width = l + 7

Hence,

Width = 37 + 7 = 44 feets

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3 years ago
Given that (x+y+z)(xy+xz+yz)=18 and that x^2(y+z)+y^2(x+z)+z^2(x+y)=6 for real numbers x, y, and z, what is the value of xyz?
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4

Step-by-step explanation:

(x+y+z)(xy+xz+yz)=18 Equation 1

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Let's expand equation 1:

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3 years ago
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3 years ago
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