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klasskru [66]
4 years ago
8

Solve the inequality 7 x ≤ 10.

Mathematics
2 answers:
nasty-shy [4]4 years ago
8 0

x ≤ 10/7 is ur answer

have a good day

Rufina [12.5K]4 years ago
5 0

Answer:

x ≤ 10/7  or as a mixed number  x ≤ 1 3/7

Step-by-step explanation:

7 x ≤ 10

We want to isolate x

Divide each side by 7

7x/7≤ 10/7

x ≤ 10/7

Changing from an improper fraction to a mixed number

x ≤ 1 3/7

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In ABC, CT is a median. What is the measure of AB?
Step2247 [10]

Answer:

AB = 102

Step-by-step explanation:

the median CT bisects the side AB at T , then

BT = AT , that is

7x + 9 = 5x + 21 ( subtract 5x from both sides )

2x + 9 = 21 ( subtract 9 from both sides )

2x = 12 ( divide both sides by 2 )

x = 6

then

AB = 5x + 21 + 7x + 9 = 12x + 30 = 12(6) + 30 = 72 + 30 = 102

4 0
2 years ago
4c divided by 6 + 2a for c= 4 for a =5
Shalnov [3]

Answer:

<u><em>1</em></u>

Step-by-step explanation:

<u>Given values :</u>

<em>a = 5</em>

<em>c = 4</em>

<u>Substitution :</u>

<em>4c / 6 + 2a</em>

<em>4(4) / 6 + 2(5)</em>

<em>16/16</em>

= <u><em>1</em></u>

8 0
3 years ago
Read 2 more answers
Write the equation of the parabola that has the vertex at point (− 1/2 ,2.3) and passes through the point (5,2 3/4 ).
Alex73 [517]

Answer:

The equation of parabola in vertex form is y=0.015(x+0.5)^2+2.3

Step-by-step explanation:

Given coordinate of vertex is (-\frac{1}{2},2.3) and the parabola passes through the point (5,2\frac{3}{4})

So, the equation of parabola in vertex form is

y=a(x-h)^2+k

Where (h,k) is the coordinate of the vertex.

(h,k)=(-\frac{1}{2},2.3)=(-0.5,2.3).\\\\So,\ h=-0.5\ and\ k=2.3

Plugging these value in equation we get,

y=a(x-(-0.5))^2+2.3\\\\y=a(x+0.5)^2+2.3

Now, we will find the value of a

Plug the coordinate (5,2\frac{3}{4})

(x,y)= (5,2\frac{3}{4})\\\\(x,y)=(5,\frac{11}{4})\\\\(x,y)=(5,2.75)

2.75=a(5-(-0.5))^2+2.3\\\\2.75=a(5+(0.5))^2+2.3\\\\2.75=a(5.5)^2+2.3\\\\2.75=a\times30.25+2.3\\\\2.75-2.3=a\times30.25\\\\0.45=a\times30.25\\\\\frac{0.45}{30.25}=a\\ \\a=0.0149

Plug the value of a in the equation y=a(x+0.5)^2+2.3

So, the equation of parabola with vertex (-\frac{1}{2},2.3) and passes through the point (5,2\frac{3}{4}) is

y=0.0149(x+0.5)^2+2.3 ≅y=0.015(x+0.5)^2+2.3

5 0
3 years ago
PLEASE HELP<br><br> which graph represents the given inequality y &lt; 3x-4
STatiana [176]

Answer: Here is the answer.

Step-by-step explanation:

6 0
3 years ago
I just need help with 4-6
Alik [6]
Think of it as subtracting 4-4 which is 0 and subtracting that remainder two.
4-6=-2
6 0
4 years ago
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