View answer attached below
Answer:
C. No. The sum of the dimensions of the eigenspaces equals nothing and the matrix has 3 columns. The sum of the dimensions of the eigenspace and the number of columns must be equal.
Step-by-step explanation:
Here the sum of dimensions of eigenspace is not equal to the number of columns, so therefore A is not diagonalizable.
<span>x intercept when f(x) = 0
so
</span><span>x^2-81 = 0
x^2 = 81
x = + 9 and x = -9
Answer
</span><span>C -9</span>
PART A
s = <span>the number of packets of strawberry wafers ;
c = </span><span>the number of packets of chocolate wafers ;
3 </span>× s + 1 × <span>c = 30 ;
s + c = 22 ;
PART B
</span>The method of solving "by substitution"<span> works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.
</span>
c = 30 - 3s;
s + ( 30 - 3s ) = 22;
30 - 2s = 22;
30 - 22 = 2s;
8 = 2s;
s = 4 ;
c = 30 - 12 ;
c = 18 ;
