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3 years ago

The question.

1 answer:

3 0

The solution to this problem can be found by taking 20% of $62.50:

0.2(62.5) = 12.5

The way the question is worded is confusing, but I think it's asking how much of a discount you would get. You would receive a $12.50 discount.

You might be interested in

If f(x) = 2x+7 and g(x) = -3x+5, what is f(g(1))?

Murrr4er [49]

Answer:

$f(g(1))=11$

Step-by-step explanation:

So we have the two functions:

$f(x)=2x+7\text{ and } g(x)=-3x+5$

And we want to find f(g(1)).

So, let's find g(1) first:

$g(x)=-3x+5$

Substitute 1 for x:

$g(1)=-3(1)+5$

Simplify:

$g(1)=-3+5$

Add:

$g(1)=2$

So:

$f(g(1))=f(2)$

Now, substitute 2 for x in f(x):

$f(x)=2x+7\\f(2)=2(2)+7$

Multiply:

$f(2)=4+7$

Add:

$f(2)=11$

So:

$f(g(1))=11$

8 0

3 years ago

Which is the most appropriate unit to measure the length of a slice of pizza?

Ne4ueva [31]

A centimetre is the most appropriate unit

6 0

3 years ago

What is the volume in cubic units of a cylinder diameter 6 and height 4

katrin2010 [14]

Hey there!

The formula for the volume of a cylinder is $\pi r^{2} h$ , which is essentially the base multiplied by the height.

If our diameter is six, then our radius is three, so we can solve for our base below. We will use 3.14 for pi.

$3^{2}(3.14)=28.26$

Now, we multiply this by our height of four.

$28.26(4)=113.04$

Therefore, our volume is 113.04 cubic units.

I hope this helps!

3 0

2 years ago

Sketch the curve y = \sqrt{x+3} .

Ierofanga [76]

The area bounded by the curve, x-axis and y-axis of the function y = √(x + 3) is 2√3

<h3>How to determine the area bounded by the curve, x-axis and y-axis?</h3>

The curve is given as:

y = √(x + 3)

The area bounded by the curve, x-axis and y-axis is when x = 0 and y = 0

When y = 0, we have:

0 = √(x + 3)

This gives

x = -3

So, we set up the following integral

A = ∫ f(x) d(x) (Interval a to b)

This gives

A = ∫ √(x + 3) d(x) (Interval -3 to 0)

When the above is integrated, we have:

A = 1/3 * [2(x + 3)^(3/2)] (Interval -3 to 0)

Expand

A = 1/3 * [2(0 + 3)^3/2 - 2(-3 + 3)^3/2]

This gives

A = 1/3 * 2(3)^3/2

Apply the law of indices

A = 2(3)^1/2

Rewrite as:

A = 2√3 or 3.46

Hence, the area bounded by the curve, x-axis and y-axis of the function y = √(x + 3) is 2√3