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inysia [295]
3 years ago
10

Hey can you help me fast!!

Mathematics
1 answer:
Sonja [21]3 years ago
6 0
The answer is -6/7 after working it out.
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In the course of a short race, a car does 50,000 J of work in 7 s. What is the power of the car during the race? (round to the n
nirvana33 [79]

Answer:

Work done is the product of distance and force, it is measured in joules.

Power is the rate of work done given by dividing the work done by time

Power (watts)= workdone (J)/ time (s)

                     = 50,000J/7 sec

                     = 7142.857 watts

Therefore, the power of the car during the race was 7142.857 watts

Step-by-step explanation:

4 0
3 years ago
Two similar cylinders have a scale factor of (1.6/3). Find the ratio of their volumes.
Tanzania [10]
Volume of cylinders = pi x r^2 x height

Simplifying the ratio:
1.6/3 = 16 / 30 (multiply and divide by 10 to remove the decimal)
<span>
Volume Ratio = 512:27</span>
3 0
3 years ago
Read 2 more answers
a car cost $20,000 when it was purchased. the value of the car depreciates by 8% each year. find the rate of decay each month.
Amanda [17]
Hi there

the rate of decay each month
0.08÷12months=0.00667
0.00667×100=0.667% each month

Hope it helps
5 0
4 years ago
Read 2 more answers
She buy candy for $1.80 and other one but she only have $20so how much she have left?
Verdich [7]
$16.40 because she bought 2 candies so you will add 1.80 +1.80 or could of times 1.80x2 then subtract $20 for what you get adding or multiplying then that's how you get what she has left.
5 0
3 years ago
Ln60-ln4 = ln(x^2 + 2x )
Sliva [168]
The answer you're looking for is, x = 3,-5
3 0
3 years ago
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