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Phoenix [80]
3 years ago
6

Hello, I need some help

Mathematics
1 answer:
____ [38]3 years ago
8 0
Graph shows x at 6 and y at -2

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What is the fifth term of the geometric sequence a1=120, a2=36, a3=10.8, a6=0.2916?
iragen [17]
First we need to find the common ratio by dividing the second term by the first term. 36/120 = 3/10

an = a1 * r^(n-1)
n = term to find = 5
a1 = first term = 120
r = common ratio = 3/10
now we sub and solve
a5 = 120 * 3/10^(5 - 1)
a5 = 120 * 3/10^4
a5 = 120 * .0081
a5 = 0.972 <=== fifth term

or we could have just done this......since we multiply by 3/10 to find the next number...
a3 = 10.8......10.8 * 3/10 = 3.24 <== 4th term
3.24 * 3/10 = 0.972 <== fifth term
5 0
3 years ago
Read 2 more answers
HELPP ITS 6 GRADE MATHS LOLLLL
Citrus2011 [14]

Answer:

-4

Step-by-step explanation:

Because if you look on a number line, -4 is more on the left, and because it is smaller.

7 0
3 years ago
Read 2 more answers
Is 3x + x=3x true or false? If false, write the correct answer
myrzilka [38]

Answer:

This is true if x equals 0

Step-by-step explanation:

8 0
3 years ago
find the nearest two positive coterminal angles and the nearest two negative coterminal angles for 420°
RSB [31]

Answer:

Positive Coterminal Angles = 60°,780°

Negative Coterminal Angles = -300°, -660°

Step-by-step explanation:

<h3>Positive Coterminal Angles:</h3>

To find nearest two coterminal angle of 420°:

1) Subtract 360° from 420°:

420°- 360° = 60° (First Positive Coterminal Angle)

2)Add 360° to 420°:

420°+ 360° =780° (Second Positive Coterminal Angle)

<h3>Negative Coterminal angles:</h3>

To find nearest two negative coterminal angles of 420°. We' lave to take the value below 0.

1) Substract 360° from 420°

420°- 360° = 60°

Which is still a positive value.

2) Again Substract 360° from 60°

60°- 360° = -300° (First Negative Coterminal Angle)

3)Subtract 360° from -300°

-300°- 360° = -660° (Second Negative Coterminal Angle)

3 0
4 years ago
What is the point-slope form of the equation for the line with a slope of 6/19 that passes through the point (−1,75)?
Umnica [9.8K]

Answer:

The answer is

<h2>y =  \frac{6}{19} x +  \frac{1431}{19}</h2>

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1)

where

m is the slope

( x1 , y1) is the point

From the question the point is (−1,75) and slope 6/19 is

y - 75 =  \frac{6}{19} (x + 1) \\ y - 75 =  \frac{6}{19} x +  \frac{6}{19}  \\ y =  \frac{6}{19} x +  \frac{6}{19}  + 75

We have the final answer as

y =  \frac{6}{19} x +  \frac{1431}{19}

Hope this helps you

5 0
3 years ago
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