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aev [14]
2 years ago
6

The ratio table shows the weights for different amounts of snow. Find the unit rate in pounds per cubic foot. Give your answer i

n decimal form.

Mathematics
2 answers:
PolarNik [594]2 years ago
6 0

The answer to your question is 8.75

kykrilka [37]2 years ago
4 0

Answer:

1.75

Step-by-step explanation:

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use the substitution method to solve the system of equations. Choose the correct ordered pair. y=4x 8x+y=18
tino4ka555 [31]

Answer:

(3/2, 6)

Step-by-step explanation:

y = 4x

8x + y = 18

this says y is 4x so you can replace y with 4x

8x + 4x = 18

12x = 18

/12      /12

  x  = 3/2


now sub x into y = 4(3/2)

y = 12/2

y = 6

8 0
3 years ago
Read 2 more answers
Can anyone show me the steps to factor 3x^2+7x+2?
Helga [31]
Ac method
for
ax^2+bx+c
multiply a and c together
find what 2 numbers multiply to get ac and add to get b
split b up
gropu
factor

3x^2+7x+2
2 times 3=6
what 2 numbers multily to get 6 and ad to get 7
6 and 1
3x^2+6x+1x+2
(3x^2+6x)+(1x+2)
3x(x+2)+1(x+2)
(3x+1)(x+2) is factored
5 0
3 years ago
Read 2 more answers
Can y’all help me plz?
gulaghasi [49]

Answer:

13

Step-by-step explanation:

Pythagreom Therom:

a^2+b^2=c^2

12^2+5^2=c^2

144+25=c^2

169=c^2

c=13

3 0
2 years ago
What is the solution to the system of equations?
MariettaO [177]

Answer:

x=-4 y=-1

Step-by-step explanation:

Let's solve your system by substitution.

−3x−8y=20;y=5x+19

Rewrite equations:

y=5x+19;−3x−8y=20

Step: Solve y=5x+19for y:

y=5x+19

Step: Substitute5x+19foryin−3x−8y=20:

−3x−8y=20

−3x−8(5x+19)=20

−43x−152=20(Simplify both sides of the equation)

−43x−152+152=20+152(Add 152 to both sides)

−43x=172

−43x

−43

=

172

−43

(Divide both sides by -43)

x=−4

Step: Substitute−4forxiny=5x+19:

y=5x+19

y=(5)(−4)+19

y=−1(Simplify both sides of the equation)

Answer:

x=−4 and y=−1

 

7 0
2 years ago
If 2tanA=3tanB,then prove that tan(A-B)=sin2B/(5-cos2B) ...?
andreev551 [17]
Tan ( A - B ) = ( tan A - tan B ) / ( 1 + tan A tan B )
tan A = 3 tan B/2
tan ( A - B ) = ((3 tan B/ 2)-tan B) / ( 1 + 3 tan² B/2)=
= (tan B/2)  / ( 2 + 3 sin²B/cos²B )=
= (sin B / cos B) / (( 2cos² B+3sin²B)/cos²B)=
=( sin B cos B ) / ( 2 cos²B + 3 ( 1 - cos² B ) ) =
= (sin B cos B ) / ( 2 cos² B + 3 - 3 cos² B ) =
= ( sin 2 B ) / 2 ( 3 - cos² B ) =
= ( sin 2 B ) / ( 6 - cos² B )=
= ( sin 2 B ) / ( 5 + 1 - 2 cos² B )=
= ( sin 2 B ) / ( 5 + sin² B + cos ² B - 2 cos² B ) =
= ( sin 2 B ) / ( 5 - ( cos² B - sin² B ) ) =
= ( sin 2 B ) / ( 5 - cos 2 B )  - correct 
8 0
2 years ago
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