Answer:
-7 =x
Step-by-step explanation:
−30=5(x+1)
Divide each side by 5
−30/5=5/5 (x+1)
-6 = x+1
Subtract 1 from each side
-6-1 = x+1-1
-7 =x
There are 120 different combinations.
There are 5 to use for the first bead; then after it is used, 4 for the second; 3 for the third; 2 for the fourth; and 1 for the fifth and last bead:
5*4*3*2*1 = 120.
Answer: f(x) approaches infinity
Step-by-step explanation:
N/A
keeping in mind that 21 months is more than a year, since there are 12 months in a year, then 21 months is really 21/12 years.


so, clearly, you can see who's greater.
Answer:
Step-by-step explanation:
4(y+7)=4(y)+4(7)
=4y+28