ALTITUDE
the altitude is the height of the traignel
if we graph the points, we get some lopsided triangle
so we know the altitude is peerpendicular to the base
so find the line that is perpendicular to the line tha passes through A and C
so first fid the line that passes through (-4,-2) and (18,-8)
slope=(y2-y1)/(x2-x1)
slope=(-8-(-2))/(18-(-4))=(-8+2)/(18+4)=-6/22
perpendicular lines have slopes the multipy to -1
-6/22 times what=-1
times both sides by -22/6
wat=22/6
that is the slope of the line that is the altitude
we have to use point slope form
the equation of a line that passes through (x1,y1) and has sloe of m is
y-y1=m(x-x1)
so passes through B (4,4) and has slope of 22/6
y-4=22/6(x-4)
y-4=22/6x-44/3
y=(22/6)x-32/3
that is the altitude
MEDIAN
the media is the line joining the midpoint of one side to the vertex of the other
so we need to find the line that passes through the midpoint of AB and through the point C
midpoint of (x1,y1) and (x2,y2) is
((x1+x2)/2,(y1+y2)/2)
so
midopint of (-4,-2) and (4,4) is
((-4+4)/2,(-2+4)/2)=(0/2,2/2)=(0,1)
so we just find the line that passes through (0,1) and (18,-8)
slope iis (-8-1)/(18-0)=-9/18=-1/2
a point is (0,1) and sloe si -1/2
y-1=-1/2(x-0)
y-1=1/2x
y=(1/2)x+1
ALTITUDE
y=(-6/22)x
MEDIAN:
y=(1/2)x+1
-1 = 3(5) + b
-1 = 15 + b
-16 = b
y = 3x -16
y - 5 = 3(x +1)
Divide by how many sides there are I think
<h2>m=(2xw)-6</h2>
Step-by-step explanation:
Let the number of women in the committee be .
Let the number of men in the committee be .
Since it is given that the number of men are 6 less than twice the number of women,
Twice the number of women is
Twice the number less six is
Since it is given that the committee has a total of 45 members,
the total number of men and women is 45.
So,
using (i) and (ii),