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Nonamiya [84]
3 years ago
14

Each student in her 8th grade math class presented her with a cookie. One-third of the students each gave her an oatmeal cookie,

one-sixth of the students each gave her a cinnamon cookie, one-fourth of the students each gave her a chocolate chip cookie, and the remaining 9 students each gave her a peanut butter cookie. How many students are in Mrs Vo's 8th grade math class?​
Mathematics
1 answer:
dezoksy [38]3 years ago
3 0

Answer:

36. There are 36 students in the class.

Step-by-step explanation:

4/12 oatmeal

2/12 cinnamon

3/12 chocolate

9 peanut

The fractions added together = 9/12

This means the 9 students = 3/12 of the class

3 x 4 = 12

9 x 4 = 36

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Step-by-step explanation:

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Which statements are true given the histogram? Check all that apply.
vova2212 [387]

Answer:

(a)The histogram is symmetrical. FALSE  

(b) The histogram is evenly distributed.  FALSE

(c) The cluster from 4 p.m.-10 p.m. means that most of  the texts were sent in the afternoon and evening. TRUE  

(d) More texts were sent from 6 p.m.-8 p.m. than from 8  p.m.-10 p.m.  FALSE.  

(e)The peak from 4 p.m.-6 p.m. means that the highest  number of texts was sent during this interval. TRUE

Step-by-step explanation:

(a)The histogram is symmetrical.  

FALSE, as the histogram has no line of symmetry.

(b) The histogram is evenly distributed.  

FALSE,  the histogram is not evenly distributed as there is no data in the  

10: AM to 3:00 PM slot.

(c) The cluster from 4 p.m.-10 p.m. means that most of  the texts were sent in the afternoon and evening.

TRUE, the data shows that the most texts were sent in afternoon and evening as it has the highest peaks in the given slot.

(d) More texts were sent from 6 p.m.-8 p.m. than from 8  p.m.-10 p.m.

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The number of texts sent  from 8  p.m.-10 p.m = 29

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8 0
3 years ago
Read 2 more answers
Can someone please help me find the value of X
Katena32 [7]

Answer:

<h2>7 </h2>

solution,

CD=3x-12

AB=14

BD=6

AC=21

Angle bisector theorem ,

\frac{ab}{bd}  =  \frac{ac}{cd}  \\  \: or \:  \frac{14}{6}  =  \frac{21}{3x - 12}  \\ or \: 14(3x - 12) = 21 \times 6( \: cross \: multiplication) \\ or \: 42x - 168 = 126

Adding 168 on both sides

or \: 42x - 168 + 168 = 126 + 168 \\ or \: 42x = 294

dividing 42 on both side

\frac{42x}{42}  =  \frac{294}{42}  \\

x = 7

Hope this helps..

Good luck on your assignment..

6 0
3 years ago
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