We will get the number of possible selections, and then subtract the number less than 25 cents.
We can choose the number of dimes 5 ways 0,1,2,3 or 4.
We can choose the number of nickels 4 ways 0,1,2 or 3.
We can choose the number of quarters 3 ways 0,1, or 2.
That's 5*4*3 = 60 selections
Now we must subtract from the 60 the number of selections of coins that are less than 25 cents. These will involve only dimes and nickels.
To get a selection of coin worth less than 25 cents:
If we use no dimes, we can use 0,1,2 on all 3 nickels.
That's 4 selections less than 25 cents. (that includes the choice of No coins at all in the 60, which we must subtract).
If we use exactly 1 dime , we can use 0,1,2, or all 3 nickels.
That's the 3 combinations less than 25 cents.
And there is 1 other selection less than 25 cents, 2 dimes and no nickels.
So that's 4+3+1 = 8 selections which we must subtract from the 60.
Answer 60-8 = 52 selections of coins worth 25 cents or more.
Since x=8y, subsitute 8y for x in other equation
y=6x-11
y=6(8y)-11
y=48y-11
minus y both sides
0=47y-11
add 11 to both sides
11=47y
divide both sides by 47
subsitute taht for y to find x
x=8y
in (x,y) form
(x,y)
Answer:
(x, y) = (3, -4)
Step-by-step explanation:
See the attached for a graph.
Answer:
45%
Step-by-step explanation:
Answer:
89 rooms should be set for early book customer
Step-by-step explanation:
According to the given data we have the following:
OVERAGE(CO) = 200
SHORTAGE(CS) = 500
In order to calculate how many rooms should be set for early book customer we would have to use the following formula:
OPTIMAL BOOKING = MEAN + (Z * STDEV)
MEAN = 75
STDEV = 25
SERVICE LEVEL= CS / (CS + CO) = 500 / (500 + 200) = 0.7143
Z VALUE FOR 0.7143 = 0.57
OPTIMAL BOOKING = 75 + (0.57 * 25) = 89
89 rooms should be set for early book customer
