I will show you how to do the first one.....we are finding the GCF...the largest number that goes into each number (same for variables)
1.) 20yx , 80x³ ( factor each number and variable)
20 = 2, 4, 5, 10, 20
y = y
x = x
80 = 2, 4, 5, 8, 10, 16, 20, 40, 80
x³ = x, x, x
what is the largest number that 20 and 80 have in common? 20...
how about the variables? x
so, the Greatest Common Factor (GCF is 20x)
Anything between -3≤x<3
Those integers can be -2,-1,0,1 or 2
Answer:
.
Step-by-step explanation:
The given expression is
We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.
Using properties of exponents, we get
![[\because a^ma^n=a^{m+n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5Ema%5En%3Da%5E%7Bm%2Bn%7D%5D)
![[\because a^{-n}=\dfrac{1}{a^n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E%7B-n%7D%3D%5Cdfrac%7B1%7D%7Ba%5En%7D%5D)
We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.
Therefore, the required expression is .
The given data is
Scores: 90-99 80-89 70-79 60-69 50-59
Students: 3 7 12 4 4
Because we are to take the middle value for each group.
Therefore the total score is
Sx = 3*94.5 + 7*84.5 + 12*74.5 + 4*64.5 + 4*54.5 = 2245
The number of students is 3+7+12+4+4 = 30
The mean is
m =2245/30 = 74.833
Calculate (Sx - m)²
(Sx - m)² = 3*(94.5-74.833)² + 7*(84.5-74.833)² + 12*(64.5-74.833)²
+ 4*(64.5-74.833)² + 4*(54.5-74.833)² = 3896.7
Calculate the standard deviation
s = √(3896.7/29) = 11.592
Answer:
mean = 74.83
std. deviation = 11.59
Answer:
-7
Step-by-step explanation:
The numerical coefficient of 
is - 7.
