y+z=10
x+z=8
x+y=12
(y+z)-(x+z)=10-8
y-x=2
y-x=2
y+x=12
solve simultaneously
x=5, y=7
then substitute to get z=3
hence xyz=573
These is yes!!! algebra one or two
Answer:
lies between 0 and 1.
Step-by-step explanation:
We must have in mind that given average weight of a newborn panda is a non-integer rational number, such that lies between two integer rational number. In other words, this number must satisfy the following condition:
, 
Which is now developed mathematically to deduce a useful expression to find integers:
1) Given
2) 
Modulative property
3) 
Existence of Multiplicative inverse/Definition of division.
4) ![(n\cdot b)\cdot b^{-1} < a\cdot b^{-1}< [(n+1)\cdot b] \cdot b^{-1}](https://tex.z-dn.net/?f=%28n%5Ccdot%20b%29%5Ccdot%20b%5E%7B-1%7D%20%3C%20a%5Ccdot%20b%5E%7B-1%7D%3C%20%5B%28n%2B1%29%5Ccdot%20b%5D%20%5Ccdot%20b%5E%7B-1%7D)
Commutative, Associative and Distributive properties.
5) 
Compatibility with Multiplication/Existence of Multiplicative Inverse/Modulative Property/Result.
If we know that 
and 
, the following inequation is formed:
It is quite evident to conclude that lies between 0 and 1.
Answer:
Option B. $0.70
Step-by-step explanation:
First day fine = $0.10
Second day fine (doubled or $0.30 which is lesser)
= $0.10 + $0.10 [$0.10 is lesser than $0.30]
= $0.20
Third day fine = $0.20 + $0.20 [ $0.20 is lesser than $0.30]
= $0.40
Fourth day fine = $0.40 + $0.30 = $0.70
[$0.30 is cheaper than doubling the amount $0.40 + $0.40]
Therefore, the total fine for a book on the fourth day is $0.70
