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Anettt [7]
3 years ago
8

HELP ME PLEASE ASAP!?Which of the following is most likely the next step in the series?

Mathematics
1 answer:
nadya68 [22]3 years ago
5 0

Answer:

B. because the first one has 3 sides second has 4 third has 5 and B. has 6

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6 is 15% of what number
navik [9.2K]
To solve this problem, you must set it up like this : 6/x = 15/100
Now, cross-multiply. 15x = 600
Divide by 15 on each side. 
x=40. 

6 is 15% of 40. 

Hope this helps :)
5 0
3 years ago
Read 2 more answers
The scale factor for the reduction is . The length of What is the length of B? B = feet
lord [1]

Answer: 1/5, 5

Step-by-step explanation:

4 0
3 years ago
Find (f/g) (x) and state the domain restriction. f (x) = 6x - 3 and g(x) = 12x^2 - 6x
Rufina [12.5K]

9514 1404 393

Answer:

  (f/g)(x) = 1/(2x)

  x ≠ 1/2

Step-by-step explanation:

  (f/g)(x)=\dfrac{f(x)}{g(x)}=\dfrac{6x-3}{12x^2-6x}=\dfrac{6x-3}{2x(6x-3)}\\\\\boxed{(f/g)(x)=\dfrac{1}{2x}}\quad x\ne\dfrac{1}{2}

The domain restriction x ≠ 1/2 comes from the requirement to prevent the denominator factor 6x-3 from being zero.

8 0
3 years ago
The sum of the digits of a two-digit nunber is 7. When you reverse the digits of the original number the new number is 27 more t
anzhelika [568]

Answer:

25

Step-by-step explanation:

2+5=7

25 reversed is 52

52-25=27

8 0
3 years ago
Read 2 more answers
1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x
qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is (2x+10)^\circ, so the measure of arc DF is

m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ

The inscribed angle theorem tells us that the central angle subtended by arc DF, \angle DOF, has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

m\angle DOF=2m\angle OEF=64^\circ

so the measure of arc DF is also 64 degrees. So we have

170-2x=64\implies106=2x\implies\boxed{x=53}

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}

7 0
3 years ago
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