Answer:
it's right answer is 20 percent ✌️
Answer:
34
Step-by-step explanation:
34 because i beleive so
Answer:
6.68% of students from this school earn scores that satisfy the admission requirement
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
The local college includes a minimum score of 1954 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement
This is 1 subtracted by the pvalue of Z when X = 1954. So
has a pvalue of 0.9332
1 - 0.9332 = 0.0668
6.68% of students from this school earn scores that satisfy the admission requirement
Answer:
The radius of the circle ,r= 1.43 m
The length of the side of square ,a= 2.77 m
Step-by-step explanation:
Given that
L= 20 m
Lets take radius of the circle =r m
The total parameter of the circle = 2π r
Area of circle ,A=π r²
The side of the square = a m
The total parameter of the square = 4 a
Area of square ,A'=a²
The total length ,L= 2π r+ 4 a
20 = 2π r+ 4 a
r=3.18 - 0.63 a
The total area = A+ A'
A" =π r² +a²
A"= 3.14(3.18 - 0.63 a)² + a²
For minimize the area
3.14 x 2(3.18 - 0.63 a) (-0.63) + 2 a = 0
3.14 x (3.18 - 0.63 a) (-0.63) + a = 0
-6.21 + 1.24 a + a=0
2.24 a = 6.21
a=2.77 m
r= 3.18 - 0.63 a
r= 3.18 - 0.63 x 2.77
r=1.43 m
Therefore the radius of the circle ,r= 1.43 m
The length of the side of square ,a= 2.77 m
Answer:
Shane must have collect 911 cans.
Step-by-step explanation:
Assume;
Cans collected by Shane = x
So,
Cans collected by Abha = x+178
Inequality
Cans collected by Shane + Cans collected by Abha ≥ 2,000
x + x + 178 ≥ 2,000
2 x ≥ 2,000 - 178
2 x ≥ 1,822
x ≥ 911
Shane must have collect 911 cans.