Using error concepts, it is found that the option that represents a Type I error is:
- d. Saying that the student is a music industry management major when in fact the student is a finance major.
The definitions of each type of error are as follows:
- A Type I error happens when a <u>true null hypothesis is rejected.</u>
- A Type II error happens when a <u>false null hypothesis is not-rejected.</u>
In this problem, the Hypothesis are:
- Null: Student is a finance major.
- Alternative: Student is a music industry management major.
By the definition of a Type I error, in this problem, it would consist in saying that a finance major student is a music industry management major student, hence option d is correct.
You can learn more about Type I and II errors at brainly.com/question/25225353
Answer:
![T_n = \frac{1}{4^{n-1}}](https://tex.z-dn.net/?f=T_n%20%3D%20%5Cfrac%7B1%7D%7B4%5E%7Bn-1%7D%7D)
Step-by-step explanation:
Given
![({)1, 1/4, 1/16, 1/64, 1/256, ... (})](https://tex.z-dn.net/?f=%28%7B%291%2C%201%2F4%2C%201%2F16%2C%201%2F64%2C%201%2F256%2C%20...%20%28%7D%29)
Required
The general term
The given sequence is geometric.
So first, we calculate the common ratio (r)
![r = T_2/T_1](https://tex.z-dn.net/?f=r%20%3D%20T_2%2FT_1)
So, we have:
![r = 1/4 \div 1](https://tex.z-dn.net/?f=r%20%3D%201%2F4%20%5Cdiv%201)
![r = 1/4](https://tex.z-dn.net/?f=r%20%3D%201%2F4)
The function is then calculated using:
![T_n =T_1 * r^{n-1}](https://tex.z-dn.net/?f=T_n%20%3DT_1%20%2A%20r%5E%7Bn-1%7D)
This gives
![T_n =1 * 1/4^{n-1}](https://tex.z-dn.net/?f=T_n%20%3D1%20%2A%201%2F4%5E%7Bn-1%7D)
![T_n = \frac{1}{4^{n-1}}](https://tex.z-dn.net/?f=T_n%20%3D%20%5Cfrac%7B1%7D%7B4%5E%7Bn-1%7D%7D)
1. 0.5
2. 75
3. 55
4. 15
5. 15/60
6. Not really sure
7. 5
8. 0.6
9. 1/2
10. 65
Not sure if I’m correct but hope this helps!
$425.20
6.80 times 9.5= 64.60 times 7 is 425.20.
Answer:
400000
Step-by-step explanation: