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vodka [1.7K]
2 years ago
14

If x is a positive integer divisible by 6, and x < 60, what is the greatest possible value of x?

Mathematics
1 answer:
ASHA 777 [7]2 years ago
6 0
The greatest value of x is 59
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a room in a form of a cuboid has a length of 5cm, height 8cm and breadth 0.07m. if one person can occupy a volume of 14cm3(cube)
Over [174]

Answer:

20 people

Step-by-step explanation:

The volume of a cuboid is equal to length * breadth * height.

First, we want to figure out the values relative to each other. Everything is in centimeters except the breadth, which is 0.07m. To convert meters to centimeters, we can multiply by 100: 0.07 * 100 = 7, so the breadth is 7cm.

Next, the volume is  length * breadth * height = 5cm * 7cm * 8cm = 280cm³. Each person occupies 14cm³. To find how many people can occupy the cube, we can divide the volume by the space each person takes, so

280cm³/14cm³ = 20 people

Note that we can divide because each person takes x amount of space, and the total space, z, can be represented by x * y = z, with y representing the amount of people, because we add x space for each person. Dividing both sides by x, we get y = z/x

5 0
3 years ago
there is a room 7 feet x 9 feet you lay a 1-foot wide plank from corner to corner touching all 4 walls how long is the plank
Alex73 [517]

Answer:

Step-by-step explanation:

l^2=[(7-V2)/2]^2+(9-V2/2)^2=

49-7V2+2/4+81-9V2+2/4=

49+81+4/4-16V2=

131-16V2=108.4 ft

so l=V108.4≈10.4ft

5 0
3 years ago
The work of a student to solve the equation 2(5y – 2) = 12 + 6y is shown below: Step 1: 2(5y – 2) = 12 + 6y Step 2: 7y – 4 = 12
kirza4 [7]
2(5y - 2) = 12 + 6y
7y - 4 = 12 + 6y ⇒ wrong, it has to be: 10y - 4 = 12 + 6y

so the correct answer is B 
7 0
3 years ago
Read 2 more answers
A frame of width a surrounds a 5 by 7 inch photograph. Find the expression that represents the area of the frame in terms of a.
Arada [10]
See diagram
totalarea=totallengtht times totalwidth=(2a+5) times (2a+7)=4a²+24a+35

minus original aera
which is 5 by 7 which is 35

4a²+24a+35-35=4a²+24a


3rd option I think, can't tell which is which

4 0
3 years ago
When an object with a momentum of 80 kg ´ m/s collides with an object with a momentum of –100 kg ´ m/s the total momentum after
mojhsa [17]
This is a physics problem.

The law is that the momentum is preserved: total momentum before collsion = total momentum after collision

Momentum before collision = 80 kg.m/s - 100 kg.m/s = -20 kg.m/s

Then answer is b. - 20 kg.m/s
3 0
2 years ago
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