Answer:
4.5 mL
Step-by-step explanation:
Amount of Acetaminophen prescribed is 15 mg/kg. This means for every 1 kg of the child's weight, 15 mg of Acetaminophen will be administered to the child.
Weight of the child = 9.6 kg
Since, for each 1 kg the amount of Acetaminophen is 15 mg, the amount of Acetaminophen needed for 9.6 kg will be = 9.6 x 15 = 144 mg
Therefore, the child must be administered 144 mg of Acetaminophen in total.
The strength of Acetaminophen is 160mg / 5 mL. This means 5 mL of an injection contains 160 mg of Acetaminophen. But since, the child needs 144 mg, we need to calculate in mL, the volume of injection needed for 144 mg of Acetaminophen.
160 mg of Acetaminophen is present in an injection of volume = 5mL
1 mg of Acetaminophen is present in an injection of volume = 
mL
144 mg of Acetaminophen is present in an injection of volume =
mL
Thus, 4.5 mL of the injection will contain 144mg of Acetaminophen which would be administered to the patient.
<span>There are 28 right handed students out of 31 total. So there are 31 - 28 = 3 left handed students.
The probability of choosing a left handed student is 3/31.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
Answer:
5259544316
Step-by-step explanation:
Given that:
Length of string = 7
Either begins with 2 consonants or ends with 2 vowels :
Either or :
A U B = A + B - (AnB)
Number of vowels in alphabet = 5
Number of consonants = 21
2 consonants at beginning :
First 2 consonants, then the rest could be any:
21 * 21 * 26 * 26 * 26 * 26 * 26 = 5239686816
3 vowels at the end :
First 4 letters could be any alphabet ; last 3 should be vowels.:
26 * 26 * 26 * 26 * 5 * 5 * 5 = 57122000
2 consonants at beginning and 3 vowels at the end :
21 * 21 * 26 *26 *5* 5 * 5 = 37264500
Hence,
2 consonants at beginning + 3 vowels at end 2 consonants at beginning - 2 consonants at beginning and 3 vowels At end
(5239686816 + 57122000) - 37264500
= 5259544316
Hence, number of 7 alphabet strings that begins with 2 consonants and end with 3 vowels = 5259544316
Answer:
And we can find this probability with the complement rule:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the disagreements of a population, and for this case we know the distribution for X is given by:
Where 
and 
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability with the complement rule:
Hahahahahahahahahahahahhaahahgahaahgagahagahahah
