Let M be the midpoint of side \overline{AB} of \triangle ABC. Angle bisector \overline{AD} of \angle CAB and the perpendicular b
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Perimeter of any figure is all its sides summed up
for a rectangle, with two equal pairs, that means, length + length + width + width or 2length + 2width, or 2(length + width)
but we know the length is 7/5 the width
width = w
perimeter = P
and the length is 7/5 of that
for a rectangle, with two equal pairs, that means, length + length + width + width or 2length + 2width, or 2(length + width)
but we know the length is 7/5 the width
width = w
perimeter = P
and the length is 7/5 of that