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Goryan [66]
2 years ago
5

IT"S TIMED NEED HELP ASAP! Find x

Mathematics
2 answers:
DochEvi [55]2 years ago
8 0
What do you need to find tho? Comment and I’ll tell you
marysya [2.9K]2 years ago
6 0

Answer:

x = 0.35

Step-by-step explanation:

120 = (15x +5) (22x+4) = 0.35

or x  =  −  17  −  √ 1609  66  ,  − 17  +  √ 1609  66

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So i think it would be 5/35
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What can I multiply 12 by to get 1000
Andreas93 [3]

Answer:

83.33333333333333

Step-by-step explanation:

I think this is answer.

7 0
3 years ago
A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an
Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

\tan\theta=\frac{perpendicular}{base}

Here \theta=45^{\circ} , perpendicular = 30 m  and base we can find.

thus,

\tan 45^{\circ}=\frac{30}{EA}

We know \tan 45^{\circ}=1

thus, EA =  30 m

Consider the Δ AEB,

Using trigonometric ratio,

\cos\theta=\frac{base}{hypotenuse}

Here \theta=60^{\circ} , hypotenuse = 80 m  and base we can find.

thus, \cos 60^{\circ}=\frac{base}{80}

We know, \cos 60^{\circ}=\frac{1}{2}

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

4 0
3 years ago
How can you determine the coordinates of a figure after a reflection over either axis
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If you reflect across the x-axis, the y value change from positive to negative.
If you reflect across the y-axis, the x value changes from positive to negative
5 0
3 years ago
Solve: 1/3(−6q+4)=−1/12(4q+4)
STatiana [176]

Answer:

Combine multiplied terms into a single fraction

13(−6+4)=−112(4+4)

13(−6q+4)=−112(4q+4)\frac{1}{3}(-6q+4)=\frac{-1}{12}(4q+4)31​(−6q+4)=12−1​(4q+4)

1(−6+4)3=−112(4+4)

1(−6q+4)3=−112(4q+4)\frac{1(-6q+4)}{3}=\frac{-1}{12}(4q+4)31(−6q+4)​=12−1​(4q+4)

2

Multiply by 1

3

Combine multiplied terms into a single fraction

4

Distribute

5

Multiply all terms by the same value to eliminate fraction denominators

6

Cancel multiplied terms that are in the denominator

7

Distribute

8

Subtract

16

161616

from both sides of the equation

9

Simplify

10

Add

4

4q4q4q

to both sides of the equation

11

Simplify

12

Divide both sides of the equation by the same term

13

Simplify

Show less

Solution

=1

Step-by-step explanation:

6 0
3 years ago
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