Answer:
1. 30°
2.90°
3. 12 units
Step-by-step explanation:
I can't believe there's nothing confirming that this is a parallelogram/a rhombus?! Assuming is awful, and I wish you could say you can't know for sure lol but for the sake of this answer, let's just call it a rhombus. (There was probably some context elsewhere that you didn't put over here, hopefully.)
1.
The reason I say this is: in a rhombus, the diagonals bisect the angles. This means that the diagonals split the angles they meet into two equal parts. That way, it would make sense. m∠QPR=m∠SPR=30°.
2.
If it is a rhombus, the diagonals are perpendicular to each other, so m∠QTP should be 90°.
3.
Diagnonals in a rhombus (and in any parallelogram) bisect each other, so PT=TR=6, and RP=PT+TR=12 units.
Sorry if this is all dreadfully wrong, and I hope I helped you!
Answer:
Step-by-step explanation:
17) HI ≅ UH ; GH ≅ TU ; GI ≅ TH
ΔHGI ≅ ΔUTH by Side Side Side congruent
∠G ≅ ∠T ; GI ≅ TH ; ∠GIH ≅ ∠THU
ΔHGI ≅ ΔUTH by Angel Side Angle congruent
19) IJ ≅ KD ; IK ≅ KC ; KJ ≅ CD
ΔIJK ≅ ΔKDC by Side Side Side congruent
∠J ≅ ∠D ; IJ ≅ KD ; ∠I ≅ ∠DKC
ΔIJK ≅ ΔKDC by Angle Side Angle congruent
Answer:
This is a 30-60-90 triangle so you would do this formula:
Short side (opposite the 30 degree angle) = x.
Hypotenuse (opposite the 90 degree angle) = 2x.
Long side (opposite the 60 degree angle) = x√3.
Step-by-step explanation:
Answer:
The area of the figure is 1,000 square feet
Step-by-step explanation:
we know that
The area of the kite ABCD
is equal to
![A=\frac{1}{2}[AC*BD]](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5BAC%2ABD%5D)
where
AC and BD are the diagonals of the kite
we have
substitute
![A=\frac{1}{2}[40*50]=1,000\ ft^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5B40%2A50%5D%3D1%2C000%5C%20ft%5E2)
