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Tpy6a [65]
3 years ago
7

Is it A, B, C, or D?

Mathematics
1 answer:
LiRa [457]3 years ago
4 0

Answer:

It's option D. 8(8x + 9y).

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1. m∠QPR =<br><br> 2. m∠QTP =<br><br> 3. RP =<br> Show all the work
alex41 [277]

Answer:

1. 30°

2.90°

3. 12 units

Step-by-step explanation:

I can't believe there's nothing confirming that this is a parallelogram/a rhombus?! Assuming is awful, and I wish you could say you can't know for sure lol but for the sake of this answer, let's just call it a rhombus. (There was probably some context elsewhere that you didn't put over here, hopefully.)

1.

The reason I say this is: in a rhombus, the diagonals bisect the angles. This means that the diagonals split the angles they meet into two equal parts. That way, it would make sense. m∠QPR=m∠SPR=30°.

2.

If it is a rhombus, the diagonals are perpendicular to each other, so m∠QTP should be 90°.

3.

Diagnonals in a rhombus (and in any parallelogram) bisect each other, so PT=TR=6, and RP=PT+TR=12 units.

Sorry if this is all dreadfully wrong, and I hope I helped you!

7 0
3 years ago
Write two different congruent statements that indicate the triangles in each pair are congruent( Odd number questions only)
ryzh [129]

Answer:

Step-by-step explanation:

17) HI ≅ UH   ;   GH  ≅  TU     ; GI  ≅ TH

ΔHGI  ≅ ΔUTH                by Side Side Side congruent

∠G  ≅  ∠T   ; GI  ≅  TH  ; ∠GIH  ≅ ∠THU

ΔHGI  ≅ ΔUTH                by Angel Side Angle congruent

19) IJ ≅ KD   ;  IK ≅ KC   ; KJ ≅ CD

ΔIJK ≅ ΔKDC             by Side Side Side congruent

∠J ≅ ∠D    ; IJ ≅ KD ;  ∠I ≅ ∠DKC

ΔIJK ≅ ΔKDC             by Angle Side Angle congruent

7 0
3 years ago
How do I find the missing sides in this triangle?
stiv31 [10]

Answer:

This is a 30-60-90 triangle so you would do this formula:

Short side (opposite the 30 degree angle) = x.

Hypotenuse (opposite the 90 degree angle) = 2x.

Long side (opposite the 60 degree angle) = x√3.

Step-by-step explanation:

6 0
3 years ago
Write the equation of the line with a slope of 1/6 that contains (12,-7)
tatiyna

\bf (\stackrel{x_1}{12}~,~\stackrel{y_1}{-7})~\hspace{10em} slope = m\implies \cfrac{1}{6} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-7)=\cfrac{1}{6}(x-12) \\\\\\ y+7=\cfrac{1}{6}x-2\implies y=\cfrac{1}{6}x-9

6 0
3 years ago
Read 2 more answers
When plotted on a grid, the paths between four neighborhood houses form the shape of a kite as shown.
KatRina [158]

Answer:

The area of the figure is 1,000 square feet

Step-by-step explanation:

we know that

The area of the kite ABCD

is equal to

A=\frac{1}{2}[AC*BD]

where

AC and BD are the diagonals of the kite

we have

BD=50\ ft\\AC=40\ ft

substitute

A=\frac{1}{2}[40*50]=1,000\ ft^2

3 0
3 years ago
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