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joja [24]
3 years ago
11

Write (2X -5)^2 as a tri nominal

Mathematics
2 answers:
Illusion [34]3 years ago
8 0

Answer:

4x² - 20x + 20

Step-by-step explanation:

(a - b)² = a² - 2ab + b²

a = 2x  ; b = 5

(2x- 5)² = (2x)² - 2*2x*5 + 5²  {(2x)² = 2x * 2x = 4x²}

           = 4x² - 20x + 25

bezimeni [28]3 years ago
5 0

Answer:

(2X -5)^2 as a tri nominal:

2x+2x-10

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from the point p(-2,4) if PQ is drawn perpendicular to line 7x-24y+10=0,find the eqaution of the lin PQ . also determine the len
zubka84 [21]

Answer:

7y+24x = -12

Step-by-step explanation:

Equation of line PQ in point slope form is expressed as;

y -y0 = m(x-x0)

m is the slope of {Q

(x0, y0) is the point on the line

Given the line 7x-24y+10=0

Get the slope

-24y = -7x -10

y = -7/-24 x - 10/-24

y = 7/24 x + 5/12

Slope = 7/24

Slope of the line PQ perpendicular to it = -24/7

Substitute m = -24/7 and (-2, 4) into the formula;

y - 4 = -24/7(x+2)

7(y-4) = -24(x+2)

7y - 28 = -24x-48

7y + 24x = -40 + 28

7y+24x = -12

This gives the equation of the line PQ

5 0
3 years ago
The range R and the maximum height H of a projectile fired at an inclination θ
sergiy2304 [10]

Answer:

1370 feet (3 sf)

Step-by-step explanation:

(210)²×sin(2×45)/32.2

1369.565217

3 0
3 years ago
In a study of government financial aid for college​ students, it becomes necessary to estimate the percentage of​ full-time coll
oksano4ka [1.4K]
The sample size needed to estimate the population proportion of a data within a margin of error, M, to a confidence level of 1 - α, with a previous population proportion estimate, p, is given by:

n=p(1-p)\left( \frac{z_{\alpha/2}}{M} \right)^2

Part A:

Given<span> a margin of error of 0.03 a confidence level of 95​%. Since we have know prior knowledge of the proportion estimate, we make use of the consevartive proportion estimate of 50% or 0.05.

z_{\alpha/2} for 95% confidence is 1.96.

Therefore, the required sample size is given by

n=0.5(1-0.5)\left( \frac{1.96}{0.03} \right)^2 \\  \\ =0.5(0.5)(65.33)^2=0.25(4,268) \\  \\ =1,067.11

Therefore, the required sample size is 1,068.



Part B:

Given that </span><span>prior studies have shown that about 55% <span>of​ full-time students earn​ bachelor's degrees in four years or less.</span></span>

Thus, p becomes 55% = 0.55 and the required sample size is given by

n=0.55(1-0.55)\left( \frac{1.96}{0.03} \right)^2 \\ \\ =0.55(0.45)(65.33)^2=0.2475(4,268) \\ \\ =1,056.44

<span>Therefore, the required sample size is 1,057.</span>



Part C:

When we dont know the additional infromation (i.e. in part A), we obtained that the required sample size is 1,068 but after we know the information our sample size becomes 1,057.

Though there is a difference between both sample sizes but the difference is not much and hence, the knowledge of the additional information does not have much of an effect on the sample size.

6 0
3 years ago
Find the diameter of a semicircle with an area of 76.97 square yards
Elenna [48]
Area of a semicircle = 1/2 πr²

----------------------------------------------------
Find Radius:
----------------------------------------------------
1/2πr² = 76.97
r² = 76.97 ÷ 1/2π
r³ = 49
r = √49
r = 7

----------------------------------------------------
Find Diameter:
----------------------------------------------------
Diameter = Radius x 2
Diameter = 7 x 2
Diameter = 14 yards

----------------------------------------------------
Answer: 14 yards
----------------------------------------------------
4 0
3 years ago
There are 18 chocolates in Swee Tuth's box, 2 each of 9 flavours.
Yuri [45]

Answer:

20% because if there's six different chocolates she likes and if she picks random thers a possibility of it

8 0
3 years ago
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