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enyata [817]
2 years ago
6

3g-2h+4d-d+8x2 need help.​

Mathematics
1 answer:
elena55 [62]2 years ago
6 0

Answer:

i think the answer you want is 8x^2+3d+3g-2h

Step-by-step explanation:

you have to combine like terms

the only like terms are +4d and -d which simplify to +3d

then you just write the rest out as written.

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Answer:

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Step-by-step explanation:

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3 years ago
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4x + 5y = 12 and 3x + 4y = 9.25 . Solve for systems of equations
masha68 [24]

Answer:

y=1

x=7/4

Step-by-step explanation:

4x + 5y = 12

3x + 4y = 9.25

4x + 5y = 12

12x + 16y =37

-12x -15 y =-36

12x + 16y =37

y=1

x=7/4

8 0
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HOW MANY SOLUTIONS DOES<br> THIS SYSTEN OF EQUATIONS HAVE<br><br> y = 2x + 2<br> y = 2x + 2
kherson [118]

Answer: Infinitely many solutions.

Step-by-step explanation:

7 0
3 years ago
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Expand (2 + a)9 using Pascal’s triangle.
Natalija [7]

Answer:

Step-by-step explanation:

The Pascal triangle is used to determine the coefficients of the terms when we expand the expression.

                                             1                                (A + B) ^ 0 = 1

                                         1       1                            (A +B ) ^ 1 = 1A + 1B

                                   1          2        1          (A+ B) ^ 2 = 1A^2 + 2 AB + 1B^2

By extending the triangle, you will get the 9th row, which is your expression, of the coefficients. that is

1          9       36    84    126    126    84    36    9    1

Now, fill in AB in the gaps.

1AB + 9 AB + 36AB + 84AB + 126AB + 126AB +84AB + 36AB + 9AB + 1AB

Next, you need to go from the left to fill out the exponent of A and it will go down from 9 (the exponent of the whole thing) . That is

1A^9B+9A^8B+36A^7B+84A^6B+126A^5B+126A^4B+84A^3B+36A^2B+9A^1B+1A^0B

Next will be the exponent of B. this time, you go from the right and do the same with A. You can go from the left also, but go up from 0 to 9 for the exponent of B

1A^9B^0+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+1A^0B^9

The last step is just to simplify the A^0=1 and B^0 =1 at the first and the last terms.

A^9+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+B^9

Hope you can learn the method

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