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DanielleElmas [232]
2 years ago
13

I need help with this math work

Mathematics
1 answer:
belka [17]2 years ago
7 0
B because when you plus the minus numbers you still minus it
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What is the rate of change
kow [346]
The average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.
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2 years ago
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7.42 is what percent of 50 ​?
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3.71 is the answer:)
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5 0
3 years ago
4. A value of 500 increases by 12% What is the new value?"​
Nonamiya [84]

Answer:

increase percent=12%

hom much increase

500 of 12%

500×12/100=60

new value=500+60

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3 0
3 years ago
18s^2+2g-12+15g-9s^2
algol13
Answer:

9s^2 + 17g - 12

Explanation:

(basically combine like terms)

the s^2 are like terms, so that would get you 18s^2 - 9s^2 = 9s^2

then the g’s are like terms,
15g + 2g = 17g

then the -12 is all on its own

if you put it all together:

9s^2 + 17g - 12


4 0
3 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus 4 squared divided by 9 minus the quantity of y minus 5
My name is Ann [436]

Answer:

Vertices at (-7, 5) and (-1, 5).

Foci at (-9, 5) and (1,5).

Step-by-step explanation:

(x + 4)²/9 - (y - 5)²/16 = 1

The standard form for the equation of a hyperbola with centre (h, k) is

(x - h²)/a² - (y - k)²/b² = 1

Your hyperbola opens left/right, because it is of the form x - y.

Comparing terms, we find that

h = -4, k = 5, a = 3, y = 4

In the general equation, the coordinates of the vertices are at (h ± a, k).

Thus, the vertices of your parabola are at (-7, 5) and (-1, 5).

The foci are at a distance c from the centre, with coordinates (h ± c, k), where c² = a² + b².

c² = 9 + 16 = 25, so c = 5.

The coordinates of the foci are (-9, 5) and (1, 5).

The Figure below shows the graph of the hyperbola with its vertices and foci.

6 0
3 years ago
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