Answer:
(f + g)(x) = 5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Terms/Coefficients
- Functions
- Function Notation
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
f(x) = x + 3
g(x) = -x + 2
(f + g)(x) is f(x) + g(x)
<u>Step 2: Find</u>
- Substitute in function values: (f + g)(x) = x + 3 - x + 2
- [Subtraction] Combine like terms (x): (f + g)(x) = 3 + 2
- Add: (f + g)(x) = 5
Answer:
The number in the middle is 60.
Step-by-step explanation:
The 2nd number = A
The 3rd number = B
The 4th number = C
Given:
(1) 130 + A + B = 300
(2) A + B + C = 200
(3) B + C + 10 = 100
Now, the work:
(2) can be modified to become A + B = 200 - C
Now, we can insert that into (1) and get the following;
130 + (200 - C) = 300
Open parentheses, simplify, you get C = 330 - 300.
C = 30
Using (3), we use above answer to get B + 30 + 10 = 100
Calculate, and get B = 100 - (30 + 10)
Simplify,
B = 60
There is your answer!
Cheers
Answer:
Step-by-step explanation:
Well, the 1 is in the tens place. Soooo then you add the three and then add a 0, the answer will be 30% (Sorry if that didn't make sense I tried!)
Answer:
Step-by-step explanation:
2(L+B)
Where L is the length and B is the breadth.
