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sashaice [31]
2 years ago
14

-2/3x+y=8 solve for y

Mathematics
2 answers:
Afina-wow [57]2 years ago
8 0

Answer:

y=8+2x/3

Step-by-step explanation:

I don’t rlly have one

alexira [117]2 years ago
5 0
The answer is y= 8+2x/3
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Which expression is equivalent to the expression shown ? 2 (x + 5) +3 (x2 - 5x +13)
Gnesinka [82]
\text{Use the distributive property:}\\\\a(b+c)=ab+ac

2(x+5)+3(x^2-5x+13)=(2)(x)+(2)(5)+(3)(x^2)-(3)(5x)+(3)(13)\\\\=2x+10+3x^2-15x+39=3x^2-13x+49

3 0
3 years ago
How do you simplify this?<br>x²y+xy² / y²+2/5 × xy​​​
polet [3.4K]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • How do you simplify this?
  • x²y+xy² / y²+2/5 × xy

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\sf\frac{  { x  }^{ 2  }  y+x { y  }^{ 2  }    }{  { y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy  } \\

Factor the expressions that are not already factored.

_____

<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> \downarrow

\sf \: x ^ { 2 } y + x y ^ { 2 }

Factor out xy.

\sf \: xy\left(x+y\right)

<u>DENOMINATOR</u> \downarrow

\sf{ y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy \\

Factor out 1/5.

\sf \: {\frac{1}{5}y\left(2x+5y\right)}  \\

_____

Continuing...

\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)}  \\

Cancel out y in both the numerator and denominator.

\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)}  \\

Expand the expression.

\sf\frac{x^{2}+xy}{\frac{2}{5}x+y}  \\

This can further simplified to as \downarrow

=    \boxed{\boxed{\bf\frac{5x\left(x  +y\right)}{2x+5y}}}

3 0
3 years ago
PLZZZZZZZZ HELP ME I WILL GIVE BRAINLIEST TO THE FASTEST AND MOST ACCURATE
Triss [41]

Answer:

10/1 +54/-6

Step-by-step explanation:

Is this the answer?

4 0
3 years ago
Read 2 more answers
Plz Help me for this question
kicyunya [14]

Answer:

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Step-by-step explanation:

6 0
2 years ago
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The endpoints of GH are G(3,3) and H(-7,7).<br> Find the coordinates of the midpoint M.
sesenic [268]

Step-by-step explanation:

Hey there!!

You can simply use midpoint formulae to find midpoint of the coordinates.

Here, Given that;

G(3,3) and H(-7,7).

Using midpoint formulae,

midpoint \: of \: gh =  (\frac{x1 + x2}{2}  ,\frac{y1 + y2}{2})

midpoint \: of \: gh =  (\frac{3 - 7}{2}  ,\frac{3 + 7}{2})

After simplifying it we get,

= (-2,5).

Therefore, midpoint of GH is M(-2,5).

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
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