Slope intercept form<br>.<br><br>

At Tanika's school, 3 people are chosen

likoan [24]

Your answer is three out of the people in your school.

5 0

3 years ago

Im a little stuck on this (please show how you did it)

nikklg [1K]

Answer:

all work is shown / pictured

5 0

4 years ago

Javier has four cylindrical models. The heights, radii, and diagonals of the vertical cross-sections of the models are shown in

Ronch [10]

The model in which the lateral surface meets the base at right angle is : Model 1.

<h3>What is a lateral surface?</h3>

The lateral surface of an object is all surfaces of that object excluding its base and top.

Analysis:

To know the exact model, we check for the models in which their dimensions form a Pythagorean triplet otherwise a right-angled triangle.

For Pythagorean triplet, the square of the diagonal must be equal to the sum of squares of the other two sides.

Model 1

Diagonal = 50cm, radius = 14cm, lateral height = 48cm

$(50)^{2}$ = $(14)^{2}$ + $(48)^{2}$

2500 = 196 + 2304

2500 = 2500. Forms Pythagorean triplet

Model 2

Diagonal= 37cm, radius = 6cm lateral height = 35cm

$(37)^{2}$ = $(35)^{2}$ + $(6)^{2}$

1369 = 1225 +36

1369 $\neq$ 1261

Model 3

Diagonal = 60cm, radius = 20cm lateral height = 40cm

$(60)^{2}$ = $(20)^{2}$ + $(40)^{2}$

3600 = 400 + 1600

3600 $\neq$ 2000

Model 4

Diagonal = 30cm, radius = 24cm, lateral height = 9cm

$(30)^{2}$ = $(24)^{2}$ + $(9)^{2}$

900 = 576 + 81

900 $\neq$ 657

Therefore the lateral surface model 1 meets the base at right angle

In conclusion, the lateral surface of model 1 meets the base at right angles as the dimensions form a right-angled triangle.

Learn more about Pythagorean triplet: brainly.com/question/20894813

#SPJ1

5 0

2 years ago

Read 2 more answers

Determine the x-intercept and y-intercept of the following linear equations

Blizzard [7]

Answer:

Step-by-step explanation:

the x intercept takes coordinate (x,0)

the y intercept takes coordinate (0,y)

x intercept y intercept

40: x+y=5 (5,0) (0,5)

x=0 , y=5, when y=0 x=5

41: x-y=5 (5,0) (0,-5)

x=0, -y=5 then y=-5, when y=0, x=5

42: 3x+4y=12 (4,0) (0,3)

x=0, 4y=12⇒y=12/4⇒y=3

y=0, 3x=12⇒x=12/3⇒x=4

43: 2x+3y=6 (3,0) (0,2)

x=0 , 3y=6⇒y=6/3=2

y=0 ,3y=6 ⇒ y=6/3 ⇒y=2

44: 3x+4y=-24 (-8,0) (0,-6)

x=0 , 4y=-24⇒y=-24/4 ⇒ y=-6

y=0 , 3x=-24⇒ x=-24/3⇒x=-8

45: 1/3x+2/3y=5/6 (5/2,0) (0,5/4)

x=0 , 2/3 y=5/6 ⇒12y=15 ⇒ y=15/12 ⇒y=5/4

y=0 , 1/3 x=5/6 ⇒6x=15 ⇒x=15/6 ⇒x=5/2

46: x=-2 (-2,0) no y intercept

it is vertical line , there is no y intercept

47: y=15 no x intercept (0,15)

horixzontal line, no x intercept

48: 3x-7y=8 (8/3,0) (0,-8/7)

x=0 , -7y=8 ⇒y=-8/7

y=0 , 3x=8 ⇒x=8/3

7 0

4 years ago

A blue boat and a red boat are on the same side of a lake and are 18 miles apart. The blue boat is 30 miles from a lighthouse on

rewona [7]

9514 1404 393

Answer:

red boat distance: 42 miles
angle at lighthouse: 22°

Step-by-step explanation:

The Law of Cosines can be used to find the distance from the red boat to the lighthouse.

b² = l² +r² -2lr·cos(B)

b² = 18² +30² +2·18·30·cos(120°) = 1764

b = √1764 = 42

The distance from the red boat to the lighthouse is 42 miles.

__

The angle at the lighthouse can be found using the law of sines.

sin(L)/l = sin(B)/b

L = arcsin(l/b·sin(B)) = arcsin(18/42·sin(120°)) ≈ 21.79°

The angle between the boats measured at the lighthouse is about 22°.

8 0

3 years ago

Slope intercept form.​

Slope intercept form.