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3 years ago

3 over 5 meter = __ centimeters

Mathematics

1 answer:

iogann1982 [59]3 years ago

7 0

Answer:

60cm

Step-by-step explanation:

1 meter = 100cm

3/5 x 100 = 60

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A package is shaped like a right rectangular prism. Use the dimensions shown to find the total surface area of this package

Slav-nsk [51]

Answer:

22 ft²

Step-by-step explanation:

2[ 2×1 + 3×1 + 3×2 ]

2(2 + 3 + 6)

2(11)

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4 years ago

Sturdy’s paper plates cost $3.12 for 24 plates. Tough’s paper plates cost $4.32 for 32 plates. Which is the better buy?

Ksivusya [100]

Answer:

Sturdy's paper plates

Step-by-step explanation:

Let's see how much 8 plates cost:

Sturdy

24/3=8

$3.12/3= $1.04

Tough

32/4=8

$4.32/4=$1.08

$1.04<$1.08

Because Tough's paper plates costs 4 cents more for 8 plates, Sturdy's paper plates are the better buy.

5 0

3 years ago

If f(x)=3(x+5)+4/x what is f(a+2)

dsp73

F(a+2) = 3((a+2) + 5) + 4/(a+2)

= 3a + 21 + 4/(a+2)

3 0

3 years ago

Eliminate the parameter and obtain the standard form of the rectangular equation. Ellipse: x = h + a cos(θ), y = k + b sin(θ) Us

gayaneshka [121]

Answer:

a) $(\frac{x-h}{a})^2+ (\frac{y-k}{b})^2=1$

b) $x=1+5 \,cos(\theta)\,,\,y=4\,sin(\theta)$

c) $\frac{(x-1)^2}{25}+ \frac{y^2}{16}=1$

Step-by-step explanation:

Start by isolating the trigonometric expression in both equations, ad then use the Pythagorean identity:

$cos^2(\theta)+sin^2(\theta)=1$

to obtain the standard equation of a conic.

$x=h+a\,cos(\theta)\\x-h=a\,cos(\theta)\\cos(\theta)=\frac{x-h}{a}$ $y=k+b\,sin(\theta)\\y-k=b\,sin(\theta)\\sin(\theta)=\frac{y-k}{b}$

then:

$cos^2(\theta)+sin^2(\theta)=1\\(\frac{x-h}{a})^2+ (\frac{y-k}{b})^2=1$

this is the equation of an ellipse centered at (h,k), and with horizontal axis length = 2a , and vertical axis length = 2b.

The parametric equations are those we started with:

$x=h+a \,cos(\theta)\,,\,y=k+b\,sin(\theta)$ but we need to find the appropriate parameters for the requested ellipse, as shown below.

For an ellipse of vertices (-4,0) a,d (6,0) and foci at (-2,0) and (4.0), we are dealing with an ellipse with major horizontal axis on the line y=0, and major diameter length of 10 units, so the parameter $a=5$ . The center of the ellipse is therefore at (1,0).

We recall that the vertices of a translated horizontal ellipse are located at $(a+h,k)$ and $(-a+h,k)$ , then k=0 to satisfy the information given (-4,0) & (6,0), and since $a=5$ , we deduce that $a+h = 6$ and therefore h=1.

To find "b" (the only parameter missing for the standard equation of the conic), we need the information on the foci (-2,0) and (4,0) which must equal (h-c,k) and (h+c,k) with k=0 and h=1 which then gives that c=3

Now using the formula for the parameter "c" of the foci: $c=\sqrt{a^2-b^2}$

$c=\sqrt{a^2-b^2}\\3=\sqrt{5^2-b^2}\\9=25-b^2\\b^2=25-9\\b^2=16\\b=4$

Then we can write the equation of this ellipse in standard form as:

$(\frac{x-h}{a})^2+ (\frac{y-k}{b})^2=1\\(\frac{x-1}{5})^2+ (\frac{y-0}{4})^2=1\\\\(\frac{x-1}{5})^2+ (\frac{y}{4})^2=1\\\frac{(x-1)^2}{25}+ \frac{y^2}{16}=1$

8 0

3 years ago

What is 2 divided by 2/5

11Alexandr11 [23.1K]

5 if I’m not mistaken

8 0

3 years ago

Read 2 more answers