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Vlad1618 [11]
3 years ago
14

Which is an equation for a line that passes through (-1,3) and (4. - 7)?

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
6 0
Gradient= -2
Y intercept= 1
Answer: y= -2x + 1
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I do not know how to find the x in this situation can anyone help?
julia-pushkina [17]

Answer and Step-by-step explanation:

Essentially, the figure FEHG got<em><u> scaled by a factor of 1.5</u></em>, and turned into BADC

So 2.4 times 1.5 is 3.6

3.6 = x

Hope this helps! #teamtrees #WAP (Water And Plant)

4 0
3 years ago
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Find x 6787+x=99798999?<br><br><br> dom join my remind ......28gc97d
wolverine [178]

Answer:

x=99792212

Step-by-step explanation:

get the x alone by subtracting 6787 from both sides

6787-6787+x=99798999-6787

x=99792212

Hope this helps!

5 0
3 years ago
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The population of a pigeons in a city is 100 and is growing exponentially at 20% per year. Write a function to represent the pop
NikAS [45]

Answer:

  • p(t) = 100×1.0153^(12t)
  • 1.53% per month

Step-by-step explanation:

In general, the function will be written ...

  p(t) = (initial value)×(growth factor)^t

where t is in units comparable to those applicable to the growth factor. The growth factor is found from ...

  growth factor = 1 + growth rate

Here, the growth rate is given as 20% per year, so the growth factor per year is ...

  1 +20% = 1.20

The initial value is given as 100, so we can write the exponential function as ...

  p(t) = 100×1.20^t

__

The time period units for t are supposed to be years, but we want to find the growth rate for a month. We can do that by recognizing there are 12 months in a year. In the above equation, we can use (1/12)(12t) in place of t, then figure the growth factor (and growth rate) per month.

  p(t) = 100×(1.20^(1/12))^( 12t)

  p(t) = 100×1.0153^(12t) . . . . population exponential function

This shows the monthly growth factor is 1.0153, so the monthly rate of change (growth rate) is ...

  1.0153 -1 = 0.0153 = 1.53% . . . . monthly rate of change

5 0
3 years ago
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The price of a share of stock started the day at $37. During the day it went down $3, up $1, down $7 and up $4. What was the pri
Oksana_A [137]
It started at $37.

It went down $3.
37 - 3 = 34

It went up 1.
34 + 1 = 35

It went down 7.
35 - 7 = 28

It went up 4.
28 + 4 = 32

The price at the end of the day was $32.
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There is a positive correlation between the number of times the Striped Ground Cricket chirps per second and the temperature in
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I think the answer is 85 im not sure
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