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Keith_Richards [23]
3 years ago
8

Type the correct answer in each box, Write the coordinates in the form (x, y). If necessary, use / for the fraction bar(s).

Mathematics
1 answer:
Blizzard [7]3 years ago
8 0

Answer:

point a are (-10,-4) and point I are (-3.875,-10.125)

Step-by-step explanation:

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Easy 5+5+5+5+5+5+555<br><br> this is soo easy<br> answer this for brainiest<br> 2+2+2+22+2+2+22
amm1812

Answer:

585 and 54

Step-by-step explanation:

4 0
2 years ago
92. Calculate the mean of each data set below. Can you find any shortcuts that allow you to find the mean without having to do m
dimulka [17.4K]

Calculate the mean of each data set below. Can you find any shortcuts that allow you to find the mean without having to do much calculation? Homework help  6, 10, 6, 10 11, 12, 12, 13, 12 0, 5, 4, 8, 0, 7

Answer: To find the mean of the given observations. we just need to first find the sum of the given observations and the divide the calculate sum by the total number of observations.

So here:

Sum of of observations =6+ 10+ 6+10+11+12+12+13+12+0+ 5+ 4+ 8+ 0+7=116

Number of observations = 15

Therefore, the mean =\frac{116}{15}= 7.733

5 0
3 years ago
1. The sum of the three consecutive members of the geometric sequence is 13. The proportion of the third and the first member is
aev [14]
If a = first term and r = common ratio we have

a + ar + ar^2 = 13   and ar^2 / a = r^2 = 9

so r = 3

and a + 3a + 9a = 13 
so a = 1

so they are  1,3 and 9 

2.
in geometric series we have

4 , 4r ,4r^2 , 60

Arithmetic;
 4,  4r , 4r + d ,  4r + 2d

so we have the system of equations
4r + 2d = 60
4r^2 = 4r + d
From first equation
2r + d = 30 
so d = 30 - 2r 
Substitute for d in second equation:-
4r^2 - 4r - (30-2r) = 0
4r^2 - 2r - 30 =0

2r^2 - r - 15 = 0
(r - 3)(2r + 5) = 0
r  = 3 or -2.5
r must be positive so its = 3
and d = 30 - 2(3) = 24

and the numbers are 4*3 =  12 , 4*3^2 = 36

first 3  are  4 , 12 and 36  ( in geometric)
and last 3 are 12, 36 and 60  ( in arithmetic)

The 2 numbers we ause are 12 and 36.





7 0
3 years ago
Find the formula for the area A and the perimeter P of the shape shown find the area and perimeter when R is 5 cm find R when A
Ghella [55]

Answer:

1)Area; A = ¼πr²

Perimeter; P = πr/2 + 2r

2)A = 19.63 cm²

P = 17.85 cm

3) r = 8.885 cm

4) r = 14 cm

Step-by-step explanation:

This is a quadrant of a circle. Thus;

Area of a circle is πr². A quadrant is a quarter of a circle. Thus;

Formula for Quadrant Area is; A = ¼πr²

A) Perimeter of a circle is 2πr. Thus, perimeter of a quadrant is a quarter of the full circle perimeter.

Formula for the quadrant perimeter in the image given is;

P = 2πr/4 + 2r

P = πr/2 + 2r

B) When r is 5 cm;

A = ¼π(5)²

A = 19.63 cm²

P = π(5)/2 + 2(5)

P = 17.85 cm

C) when A is 100cm²:

¼πr² = 100

r² = 100 × 4/π

r² = 78.9358

r = √78.9358

r = 8.885 cm

D) when P = 50 cm.

50 = πr/2 + 2r

50 = (½π + 2)r

r = 50/(½π + 2)

r = 14 cm

6 0
3 years ago
What is the constant of variation if y varies inversely as x and y = 3 when x = 6? PLZ HELP ME I DONT UNDERSTAND
mojhsa [17]

Answer:

k = 18

Step-by-step explanation:

Given that y varies inversely as x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition y = 3 when x = 6, that is

3 = \frac{k}{6} ( multiply both sides by 6 )

18 = k

The constant of variation is k = 18

7 0
3 years ago
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