Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:
1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.
The total walkway area is thus x^2 + 4(2^2) + 4(x*2).
We want to find the dimensions of the garden. To do this, we need to find the value of x.
Let's sum up the garden dimensions and the walkway dimensions:
x^2 + 4(2^2) + 4(x*2) = 196 sq ft
x^2 + 16 + 8x = 196 sq ft
x^2 + 8x - 180 = 0
(x-10(x+18) = 0
x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.
The garden dimensions are (10 feet)^2, or 100 square feet.
Answer:
B.-38
Step-by-step explanation:
2x - 18 = y ...(1)
x = -10 (Given)
Now,
Put the value of x in equation (1) we get,
2(-10) - 18 = y
-20 - 18 = y
-38 = y
<em><u>y = -38</u></em>
Thus, the value of y is -38
Answer:
10 feet
Step-by-step explanation:
you would just have to do 5*2 which equals 10
Answer:
3
Step-by-step explanation:
g(x) = x² + 2x+4
h(x) = -3x+2
(g*h)(1) is the same as
g(h(1)) , next solve for h(1) first by substituting in h(x), x with 1
g( h( x= 1)) = g( -3*1 +2) = g( -1) so substitute in g(x) , x with -1
g(x= -1) = (-1)² +2(-1) +4 =1-2+4 =3
