10^2 = 10 × 10
10^3 = 10 × 10 × 10 = 1000
10^4 = 10 × 10 × 10 × 10
Answer:
Coefficient of skewness = 0.5785
Population standard deviation = 88.154
Step-by-step explanation:
Given the data:
Month Jan Feb Mar Apr May Jun Jul
Unit Sales 314 285 158 482 284 310 281
Reordered data : 158, 281, 284, 285, 310, 314, 482
The population mean of the data :
Mean, μ = Σx / n = 2114 / 7 = 302
The median :
1/2(n+1)th term
n = 7
1/2(8)th term
Median = 4th term = 285
The population standard deviation, s :
s = √(Σ(x - μ)²/n)
s = √[(158-302)^2 + (281-302)^2 + (284-302)^2 + (285-302)^2 + (310-302)^2 + (314-302)^2 + (482-302)^2] / 7
s= √(54398 / 7)
s = √7771.1428
s = 88.154
The Pearson Coefficient of skewness :
[3(μ - median)] / s
3(302 - 285) / 88.154
3(17) / 88.154
51 / 88.154
= 0.5785
Answer:
m<A = 30degrees
m<B = 70degrees
Step-by-step explanation:
Find the diagram attached
From the diagram;
m<A + 150 = 180
m<A = 180 - 150
m<A = 30degrees
Also since the sum of angles in a triangle is 180degrees, hence;
m<B+m<A + 80 = 180
m<B+30+80 = 180
m<B+110 = 180
m<B = 180 - 110
m<B = 70degrees
The magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T
<h3>Magnetic field inside solenoid</h3>
The magnetic field inside the central area of the solenoid is given by B = μ₀ni where
- μ₀ = permeability of free space = 4π × 10⁻⁷ Tm/A,
- n = number of turns per unit length = 3,170 turns/m and
- i = current in solenoid = 6.7 A
Since B = μ₀ni
Substituting the values of the variables into the equation, we have
B = μ₀ni
B = 4π × 10⁻⁷ Tm/A × 3,170 turns/m × 6.7 A
B = 4π × 10⁻⁷ Tm/A × 21239 A-turns/m
B = 84956π × 10⁻⁷ T
B = 266897.15 × 10⁻⁷ T
B = 0.026689715 T
B ≅ 0.0267 T
So, the magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T
Learn more about magnetic field inside a solenoid here:
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