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Scilla [17]
3 years ago
11

What is the center of the circle whose equation, in standard form, is (x – 5)2 + y2 = 4​

Mathematics
1 answer:
irina [24]3 years ago
3 0

Answer:

(5, 0)

Step-by-step explanation:

The center of the circle is determined by the numbers being subtracted from the corresponding variables.

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#3 please <br> What’s the answer &amp; how do u do it
Monica [59]

Answer:

<h2>The desired equation is y = (4/3)x - 14/3.</h2>

Step-by-step explanation:

This new line passes thru (-4, 8) and (0, 5).

As we move from (-4, 8) to (0, 5), x increases by 4 and y decreases by 3.

Thus, the slope of this line is m = rise / run = -3/4.

Thus, the slope of a line perpendicular to the given line is the negative reciprocal of -3/4:  4/3.

Thus, the equation of a line perpendicular to the given line is

y = (4/3)x + b.

This line passes thru the point (5, 2).  Thus, the following is true:

2 = (4/3)(5) + b, or 2 = 20/3 + b

Mult. this 2 by 3/3, we get 6/3, so that 6/3 = 20/3 + b.  b = -14/3.

<h2>The desired equation is y = (4/3)x - 14/3.</h2>
6 0
3 years ago
Question 2 (2 points)
katovenus [111]

Answer:

x^(2) + 14 x + 49

Step-by-step explanation:

7 0
3 years ago
For what interval is the value of (f – g)(x) negative?
Vsevolod [243]
The correct answer for the given mathematics question above would be f < g. The interval wherein the value of (f-g)(x) is negative is f < g. A function is negative on intervals when the graph line lies below the x-axis. On the other hand, a function is positive on intervals when the graph line lies above the x-axis. 
8 0
3 years ago
Read 2 more answers
What is 6[1.5d-1]=3[3d-2 solution
liubo4ka [24]
I think its 1

sorry if im wrong.










6 0
3 years ago
48<img src="https://tex.z-dn.net/?f=4%5Csqrt%7Bx%7D%2012192%5C%5C" id="TexFormula1" title="4\sqrt{x} 12192\\" alt="4\sqrt{x} 121
pentagon [3]

Answer:

= x 3048

Step-by-step explanation:

6 0
2 years ago
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