$average \: rate \: of \: fall = 16x \: feet \: per \: second \\ duration \: of \: fall \: (time) = x \: seconds \\ distance \: of \: fall = 16x \: feet \: per \: second \times x \: seconds \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =x(16x) \: feet \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 16 {x}^{2} \: feet \\ \: the \: egg \: traveled \: 16 {x}^{2} \: feet \: in \: x \: seconds.$

5 0

4 years ago

x^2-6x=-1 If the quadratic equation has real solutions, what are the solutions? Explain. Estimate irrational solutions to the ne

IgorC [24]

X^2 -6x +1 = 0
a=1
b = -6
c = 1

Use the quadratic formula
x = [-b +- sq root (b^2 -4ac)] / 2a
x = [--6 +- sq root (36 - 4)] / 2
x = [ 6 +- sq root (32)] / 2
sq root (32) = 5.657

x1 = [ 6 + 5.657] / 2
x1 = 11.657 / 2
x1 = 5.8285 
x1 = 5.82 (to nearest tenth)

x2 = [ 6 - 5.657] / 2
x2 = .343 / 2
x2 = .1715
x2 = .2 (to nearest tenth)

7 0

3 years ago

What is a counterexample for the following statement?

Citrus2011 [14]

Answer:

D.angle

Step-by-step explanation:

If two rays have the same endpoint, then they do not necessarily have to be opposite rays. They could form an angle instead.

5 0

3 years ago