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3 years ago

I got it wrong i need help please

Mathematics

1 answer:

nikdorinn [45]3 years ago

7 0

Answer:

Step-by-step explanation:

thats a right angle, 90 degrees total.

90- 46 = 44.

Try 44 !!

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Furkat [3]

Answer:

Step-by-step explanation:

8 0

3 years ago

Which equation represents the line that is perpendicular to y=1/5 and passes through (-4,-3)?

babymother [125]

Answer:

x=-4

Step-by-step explanation:

Just had it on a test and got it write

3 0

3 years ago

NARA [144]

Answer:

A) slope = p/q

Step-by-step explanation:

Slope of any given can be found using the formula, $\frac{rise}{run} = \frac{y_2 - y_1}{x_2 - x_1}$ .

In this case, using similar triangles, the rise over the run of any of the given similar triangles will give us the slope of line AB.

This means, slope of line AB would be:

$\frac{rise}{run} = \frac{m}{n} = \frac{p}{q}$ .

✅Therefore, slope of line AB = p/q

6 0

3 years ago

Find two numbers if their difference is 16 and their ratio is 5:7.

sleet_krkn [62]

7x-5x=16
2x=16
x=8
so 7*8=56
5*8=40
56:40
56-40=16

8 0

3 years ago

Read 2 more answers

This week, we are covering relationships that can be approximated by linear equations. For instance, y = 453x + 3768 represents

lana [24]

Answer:

See explanation below.

Step-by-step explanation:

We assume that the data is given by :

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

Where X represent the cost for scholarships in thousands of dollars and y represent the cost of life for an academic semester (The data comes from the web)

We can find the least-squares line appropriate for this data.

For this case we need to calculate the slope with the following formula:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

So we can find the sums like this:

$\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720$

$\sum_{i=1}^n y_i =38+43+29+32+26+33+19+27+23+14+19+21=324$

$\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200$

$\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540$

$\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=17540-\frac{720*324}{12}{12}=-1900$

And the slope would be:

$m=-\frac{1900}{6000}=-0.317$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{720}{12}=60$

$\bar y= \frac{\sum y_i}{n}=\frac{324}{12}=27$

And we can find the intercept using this:

$b=\bar y -m \bar x=27-(-0.317*60)=46.02$

So the line would be given by:

$y=-0.317 x +46.02$

We have an inverse linear relationship since the slope is negative between the variables of interest.

8 0

4 years ago