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3 years ago

Find the point of intersection for the two functions through substitution. Show

Mathematics

1 answer:

Alex777 [14]3 years ago

4 0

<h3>Answer: (-1, 11)</h3>

This means x = -1 and y = 11 pair up together.

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Work Shown:

Set the two functions equal to one another. Solve for x.

f(x) = g(x)

-4x+7 = 2x+13

7 = 2x+13+4x ... adding 4x to both sides

7 = 6x+13

7-13 = 6x .... subtract 13 from both sides

-6 = 6x

6x = -6

x = -6/6 ... divide both sides by 6

x = -1

Use this x value in either function

f(x) = -4x+7

f(-1) = -4(-1)+7

f(-1) = 11

g(x) = 2x+13

g(-1) = 2(-1)+13

g(-1) = 11

Whichever function you pick, the input x = -1 leads to the output y = 11.

The point of intersection is (x,y) = (-1, 11)

Visual confirmation is shown below.

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<h3>How to calculate the total annual premium for $x ?</h3>

If its given that the annual premium is $p per $y face value, then we can calculate the annual premium for $1 face value and then use it to calculate annual premium for $x.

Using proportions, we get:

$\rm \$y \: face \: value : \$p \: annual \: premiun\\\\\rm \$1 \: face \: value : \$\dfrac{p}{y} \: annual \: premiun\\\\\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premiun\\$

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Thus, we have p = 6.01, y = 1000

Since Jade wants to buy Life insurance for $200,000, thus, x = $200,000

Putting it in the above derived formula, we get:

$\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premium\\\\\rm \$200000\:face\: value : \$\dfrac{6.01 \times 200000}{1000} \: annual \: premium\\ = \$1202 \: annual \: premiun$