Answer:
c
Step-by-step explanation:
Imagine a ladder leaning against the wall and you know the height of the ladder and its distance from the wall and you had to find out the height you could use pythagorean theorem here
Well if pi is referred to as 3.14 then the distance around the garden would be 314.
The formula for Circumfrence is pi times diameter, so 3.14 times 100 = 314 (circumfrence)
Answer:
Step-by-step explanation:
From the given information:
the mean 
= 2300
Standard deviation = 
Standard deviation (SD) = 214.4761
TO find:
a) 



From the Z-table, since 5.595 is > 3.999

P(x > 3500) = 0.0001
b)
Here, the replacement time for the mean 
= 0.25
Replacement time for the Standard deviation 

For 115 component, the mean time = (115 × 20)+(114×0.25)
= 2300 + 28.5
= 2328.5
Standard deviation = 
= 
= 
= 
= 
= 214.482
Now; the required probability:




From the Z-table, since 8.376 is > 3.999
P(x > 4125) = 1 - 0.9999
P(x > 4125) = 0.0001