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Effectus [21]
3 years ago
8

Math class 10

Mathematics
1 answer:
Taya2010 [7]3 years ago
7 0

Answer:

11%

Step-by-step explanation:

Compound Interest Formula: initial ( 1 + interest rate )^time = final amount

Let compound interest be x

4000(1+x)^3 = 5500

Divide both sides by 4000

4000(1+x)^3 / 4000 = 5500/4000

Cube root both sides

\sqrt[3]{(1+x)^3} =\sqrt[3]{11/8}

1 + x = 2.22398 / 2

1 + x = 1.11199

Minus both sides by 1

1 + x = 1.11199

-1        -1

x = .11199 = 11%

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The table shows the hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale. Grade 7 Grade 8 20 21 15
Naddika [18.5K]

Answer:

1. The interquartile range for the grade 7 data is 6.

2. The interquartile range for the grade 8 data is 6.

3. The difference of the medians of the two data sets is 2.

4. The difference is about 1/3 times the interquartile range of either data set.

Step-by-step explanation:

The hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale is given by the following table.

Grade 7       Grade 8

  20                  21

  15                  29

  30                  14

  24                  19

   18           24

   21                 25

The data set for grade 7 is

20, 15, 30, 24, 18, 21

Arrange the data in ascending order.

15, 18, 20, 21, 24, 30

Divide the data in four equal parts.

(15), 18, (20), (21), 24,( 30)

Q_1=18, Median=\frac{20+21}{2}=20.5, Q_3=24

The interquartile range for the grade 7 data is

IQR=Q_3-Q_1=24-18=6

Therefore the interquartile range for the grade 7 data is 6.

The data set for grade 8 is

21, 29, 14, 19, 24, 25

Arrange the data in ascending order.

14, 19, 21, 24, 25, 29

Divide the data in four equal parts.

(14), 19, (21), (24), 25, (29)

Q_1=19, Median=\frac{21+24}{2}=22.5, Q_3=25

The interquartile range for the grade 8 data is

IQR=Q_3-Q_1=25-19=6

Therefore the interquartile range for the grade 8 data is 6.

The difference of the medians of the two data sets is

D=22.5-20.5=2

Therefore the difference of the medians of the two data sets is 2.

Let the difference is about x times the interquartile range of either data set.

The IQR of each data is 6.

D=x(IQR)

2=x(6)

\frac{2}{6}=x

\frac{1}{3}=x

Therefore the difference is about 1/3 times the interquartile range of either data set.

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Answer:

8 i think hope this helps

Step-by-step explanation:

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