Answer: good luck
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: the amount a 10-11-year-old spends on a trip to the mall.
Assuming that the variable has a normal distribution, you have to construct a 98% CI for the average of the amount spent by the 10-11 year-olds on one trip to the mall.
For this you have to use a Student-t for one sample:
X[bar] ± *
n= 6
$18.31, $25.09, $26.96, $26.54, $21.84, $21.46
∑X= 140.20
∑X²= 3333.49
X[bar]= ∑X/n= 140.20/6= 23.37
S²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/5[3333.49-(140.2)²/6]= 11.50
S= 3.39
X[bar] ± *
[23.37 ± 3.365 * ]
[18.66;29.98]
With a confidence level of 98%, you'd expect that the interval $[18.66;29.98] will include the population mean of the money spent by 10-11 year-olds in one trip to the mall.
I hope you have a SUPER day!
Answer:
V =110 in ^3
Step-by-step explanation:
The volume is
V = l*w*h
V = 10 * 2 * 5.5
V =110 in ^3
Answer:
Step-by-step explanation:
In general, the slope intercept form assumes the formula: y = mx + b. m is the slope (lesson on slope ) mnemonic : 'm' means 'move' b is the y -intercept ( lesson on the y-intercept ) mnemonic : 'b' means where the line begins.