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Ludmilka [50]
3 years ago
6

Given: f(x) = 5x-10, what is f(9)?

Mathematics
1 answer:
kap26 [50]3 years ago
3 0
I think the answer might be in the photo but we would need to see what we’re working with lol
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A cafe offers senior citizens a 15% discount off its regular price of $8.95 for the dinner buffet.
jonny [76]

a) 75 percent of the regular price is the price for senior citizens.

b) $6.712 is the price for senior citizens.

<u>Step-by-step explanation</u>:

  • The regular price is the 100% = $8.95
  • The offer price for senior citizen = 15% discount from 100%

∴ Percent of the regular price for senior citizens = 100% - 15% = 75%

The price for the senior citizens = 75% of $8.95

⇒ (75/100)\times8.95

⇒ 0.75\times8.95

⇒ 6.712 dollars.

∴ The price for senior citizens = $6.712

7 0
3 years ago
The temperature during the day in Miami was 92 degrees fahrenheit. During the night, the temperature fell 4 degrees fahrenheit.
BigorU [14]
You need to take away 4 degrees from 92.
"Take away" means subtraction.
92 - 4
The answer is option C.
4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bk%7D%7B3%7D%20-2k%20%2B4%20%3D10" id="TexFormula1" title="\frac{k}{3} -2k +4 =10" al
VikaD [51]

Answer:

fraction > -18/5

dec> -3.6

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Jan sold for more than three times the number of magazines Mel sold during the school fundraiser Morgan sold 40 more magazines t
pav-90 [236]

Answer: eyyyyyy my name is Jan what a coincidence

Step-by-step explanation:

3 0
3 years ago
The following data represent the monthly phone use, in minutes, of a customer enrolled in a fraud prevention program for the pas
Illusion [34]

Answer:

The answer is "717.25 minutes".

Step-by-step explanation:

In this question first, we arrange the value in ascending order that are:

307,311,321,322,354,363,377,406,425,435,461,464,474,499,505,513,517,534,548

The median is always in an orderly position that is = \frac{(n+1)}{2}.

\to \frac{(n+1)}{2} = \frac{(20+1)}{2} = 10.5  position orders

10^{th} \ and \ 11^{th} place an average of observations so, the

Average = \frac{(425 +435)}{2} = \frac{(860)}{2} =430

Because as medium stands at 10.5 that median is as below 10 are greater than the level.

Q_1 often falls throughout the ordered BELOW average is = \frac{(n+1)}{2} place.

\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}ordered position

Average 5^{th} \ and \ 6^{th}  location findings

Q_1 = \frac{(354+363)}{2} = \frac{(717)}{2}= 358.5

In  = \frac{(n+1)}{2} the ordered place, Q3 always falls ABOVE the median.

\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th} ordered At median ABOVE 

Consequently Q_3 falls between 5^{th} \ and \ 6^{th} ABOVE the median position

15^{th}\  and \ 16^{th}place average of observations

\to Q_3 = \frac{(499+505)}{2}=\frac{(1004)}{2}  = 502

\to IQR = Q_3 - Q_1= 502-358.5= 143.5  

\to \text{Upper fence} = Q_3 + 1.5 \times IQR= 502 + 1.5 \times 143.5 = 717.25

4 0
3 years ago
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