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frosja888 [35]
3 years ago
5

Examine the equation. 4(x – 3) = 4x – 12 Which of the following is true? (Check all that apply.) It is a true statement. Any inp

ut will result in an equivalent equation. It is equivalent to an equation of the form a = a. It has no solution. Only one input will result in a true statement.
Mathematics
3 answers:
Helen [10]3 years ago
8 0

Answer:

A, B, and C.

Step-by-step explanation:

We have the equation:

4(x-3)=4x-12

Let’s distribute the left. This yields:

4x-12=4x-12

Let’s add 12 to both sides:

4x=4x

And subtract 4x from both sides:

0=0

We get the true statement 0=0.

Hence, A is correct.

Because it is a true statement, <em>any</em> input will yield an equivalent output.

Hence, B is also correct.

We also have the form a=a, where a is 0.

Hence, C is also correct.

Therefore, our correct answers are A, B, and C.

goldfiish [28.3K]3 years ago
6 0

Answer:

It is a true statement.

Any input will result in an equivalent equation.

It is equivalent to an equation of the form a = a.

Naetoosmart2 years ago
0 0

if the question isn't multiple choice, its A

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What are the orders of 3,7,9,11,13,17 and 19(mod20)?does 20 have primitive roots?
bezimeni [28]
3\equiv3\mod{20}
3^2\equiv9\mod{20}
3^3\equiv27\equiv7\mod{20}
3^4\equiv3\cdot3^3\equiv3\cdot7\equiv21\equiv1\mod{20}

7\equiv7\mod{20}
7^2\equiv49\equiv9\mod{20}
7^3\equiv7\cdot7^2\equiv63\equiv3\mod{20}
7^4\equiv7\cdot7^3\equiv21\equiv1\mod{20}

9\equiv9\mod{20}
9^2\equiv3^4\equiv1\mod{20}

11\equiv11\mod{20}
11^2\equiv121\equiv1\mod{20}

13\equiv-7\equiv13\mod{20}
13^2\equiv169\equiv9\mod{20}
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13^4\equiv13\cdot13^3\equiv(-7)(-3)\equiv21\equiv1\mod{20}

17\equiv-3\equiv17\mod{20}
17^2\equiv(-3)^2\equiv9\mod{20}
17^3\equiv(-3)^3\equiv-27\equiv3\mod{20}
17^4\equiv(-3)^4\equiv81\equiv1\mod{20}

19\equiv-1\equiv19\mod{20}
19^2\equiv19(-1)\equiv-19\equiv1\mod{20}

Generally speaking, a number x coprime to n will be a primitive root of n if we have x^n\equiv x\mod{n}, or x^{n-1}\equiv1\mod{n}. In other words, if x is of order n-1 modulo n, then x is a primitive root of n.

Since none of these numbers has order 19, it follows that 20 does not have any primitive roots.
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Step-by-step explanation:

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Actually, this is worth 13 points. not 25. thanks!
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