Hello, It is very simples.
Look it :
Let a^3 - b^3 = ?
Add on both th side -3a^2b + 3ab^2
a^3 -3a^2b + 3ab^2 -b^3 = ?
-3a^2b+3ab^2
The firs equation is = (a - b)^3
Then,
(a - b)^3 = ? + 3a^2b - 3ab^2
Passing -3a^2b + 3ab^2 to the left side:
But changing the sinal
? = (a - b)^3 + 3a^2b - 3ab^2
? = (a - b)^3 + 3ab ( a - b)
Putting (a - b) as commun factor
? = (a - b).[ 3ab + (a - b)^2 ]
As (a - b)^2 = a^2 - 2ab + b^2
Then,
? = (a - b).[ 3ab + a^2 -2ab +b^2]
? = (a - b).( a^2 + ab + b^2)
I hope helps!
Answer:
4(7x+5) (x+1)
can u give me the brainiest answer
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
according to cyclic quadrilateral properties the oppoaite angles are supplementry
Answer:
y= -6/7
Step-by-step explanation:
.............. I did it, trust me
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